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3 years ago

10

Hydrogen reacts with an element to form a compound. Which element would have the most valence electrons available to react with

hydrogen?
oxygen
chlorine
neon
nitrogen

2 answers:

belka [17]3 years ago

6 0

chlorine

is the correct answer

SSSSS [86.1K]3 years ago

5 0

Answer:

Chlorine :)

Explanation:

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Three gases (8.00 g of methane, CH4, 18.0 g of ethane, C2H6, and an unknown amount of propane, C3H8) were added to the same 10.0

klemol [59]

Answer:

Partial pressure of methane: 1.18 atm

Partial pressure of ethane: 1.45 atm

Partial pressure of propane: 2.35 atm

Explanation:

Let the total moles of gases in a container be n.

Total pressure of the gases in a container =P = 5.0 atm

Temperature of the gases in a container =T = 23°C = 296.15 K

Volume of the container = V = 10.0 L

$PV=nRT$ (Ideal gas equation)

$n=\frac{PV}{RT}=\frac{5.0 atm\times 10.0 L}{0.0821 atm L/mol K\times 296.15 K}=2.0564 mol$

Moles of methane gas = $n_1=\frac{8.00 g}{16.04 g/mol}=0.4878 mol$

Moles of ethane gas = $n_2=\frac{18.00 g}{30.07 g/mol}=0.5986 mol$

Moles of propane gas = $n_3=?$

$n=n_1+n_2+n_3$

$n_3=n-n_1-n_2=2.0564 mol-0.4878 mol-0.5986 mol= 0.9700 mol$

Partial pressure of all the gases can be calculated by using Raoult's law:

$p_i=P\times \chi_i$

$p_i$ = partial pressure of 'i' component.

$\chi_1$ = mole fraction of 'i' component in mixture

P = total pressure of the mixture

Partial pressure of methane:

$p_1=P\times \chi_1=P\times \frac{n_1}{n_1+n+2+n_3}=P\times \frac{n_1}{n}$

$p_1=5.00 atm\times \frac{0.4878 mol}{2.0564 mol}=1.18 atm$

Partial pressure of ethane:

$p_2=P\times \chi_2=P\times \frac{n_2}{n_1+n+2+n_3}=P\times \frac{n_2}{n}$

$p_2=5.00 atm\times \frac{0.5986 mol}{2.0564 mol}=1.45 atm$

Partial pressure of propane:

$p_3=P\times \chi_3=P\times \frac{n_3}{n_1+n+2+n_3}=P\times \frac{n_3}{n}$

$p_3=5.00 atm\times \frac{0.9700 mol}{2.0564 mol}=2.35 atm$

5 0

4 years ago

What process produces the sediments that ultimately lead to soil formation

Gelneren [198K]

Answer:

Option: B.

Explanation:

Weathering

5 0

3 years ago

Read 2 more answers

The answer for number 1

Nuetrik [128]

Maybe B. Im probably wrong but I think b

4 0

3 years ago

Read 2 more answers

A gas has a volume of 74.0L under a pressure of 2.46 atm. If temperature remains the same and pressure is changed to 630 mmHg, w

Ulleksa [173]

Answer: 145 L

Explanation:

To calculate the new pressure, we use the equation given by Boyle's law. This law states that pressure is directly proportional to the volume of the gas at constant temperature.

The equation given by this law is:

$P_1V_1=P_2V_2$

where,

$P_1\text{ and }V_1$ are initial pressure and volume.

$P_2\text{ and }V_2$ are final pressure and volume.

We are given:

$P_1=2.46atm\\V_1=74.0L\\P_2=630mmHg=0.829atm(760mmHg=1atm)\\V_2=?$

Putting values in above equation, we get:

$2.46\times 74.0L=0.829\times V_2\\\\V_2=219L$

Volume change = (219-74.0 )L = 145 L

Thus the volume CHANGE that occurs is 145 L

4 0

3 years ago

Mole of 110 grams of NaHCO3

Ann [662]

You can use the formula triangle . You can find it on google.

5 0

3 years ago