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SVEN [57.7K]
2 years ago
6

The fastest man can run 100 meters in 10 seconds. What is his speed in miles per hour?

Chemistry
2 answers:
Anestetic [448]2 years ago
8 0

Answer:22.37 mph

Explanation:

100 meters = 0.062137 miles

Assume constant speed over the distance.

0.062137 miles in 10 sec

0.372822 miles in 60 sec = 1 minute

22.36932 miles in 60 minutes

22.37 mph rounded to 2 decimals

Vinvika [58]2 years ago
4 0
22.37 , or 36 kilometers an hour
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What is the product of the reaction between arsenic and oxygen
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For the reaction shown, calculate how many grams of oxygen form when each quantity of reactant completely reacts.
Nikolay [14]

Explanation:

Molar mass of KClO_{3} = 39.1 + 35.5 + 3(16.0) = 122.6 g

Molar mass of KCl = 39.1 + 35.5 = 74.6 g

Molar mass of O_{2} = 32.0 g

According to the equation, 2 moles of KClO_{3} reacts to give 3 moles of oxygen.

Therefore, 2 (122.6) = 245.2 g of KClO_{3} will give 3 (32.0) = 96.0 g of oxygen. Thus, 245.2 g of KClO_{3} gives 96.0 g of oxygen.

(a) Calculate the amount of oxygen given by 2.72 g of KClO_{3} as follows.

       \frac {96g}{245.2g} \times 2.72 g = 1.06 g of O_{2}


(b) Calculate the amount of oxygen given by 0.361 g of KClO_{3} as follows.

    \frac {96g}{245.2g} \times 0.361 g = 0.141 g of O_{2}


c) Calculate the amount of oxygen given by 83.6 kg KClO_{3} as follows.  

    \frac {96g}{245.2g} \times 83.6 g = 32.731 kg of O_{2}

Convert kg into grams as follows.

    \frac{32.731 kg}{1 kg} \times 1000 g = 32731 g of O_{2}


(d) Calculate the amount of oxygen given by 22.5 mg of KClO_{3} as follows.  

    \frac {96g}{245.2g} \times 22.5 mg = 8.79 mg

Convert mg into grams as follows.

  \frac{8.79 mg}{1 mg}\times 10^{-3} g = 8.79 \times 10^{-3} g of O_{2}

8 0
3 years ago
Can someone's help me with this
labwork [276]
Oh ok just wait a minute
7 0
4 years ago
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