Question

A gas has a volume of 74.0L under a pressure of 2.46 atm. If temperature remains the same and pressure is changed to 630 mmHg, what is the volume CHANGE that occurs?

Answer 1

Answer: 145 L

Explanation:

To calculate the new pressure, we use the equation given by Boyle's law. This law states that pressure is directly proportional to the volume of the gas at constant temperature.

The equation given by this law is:

$P_1V_1=P_2V_2$

where,

$P_1\text{ and }V_1$ are initial pressure and volume.

$P_2\text{ and }V_2$ are final pressure and volume.

We are given:

$P_1=2.46atm\\V_1=74.0L\\P_2=630mmHg=0.829atm(760mmHg=1atm)\\V_2=?$

Putting values in above equation, we get:

$2.46\times 74.0L=0.829\times V_2\\\\V_2=219L$

Volume change = (219-74.0 )L = 145 L

Thus the volume CHANGE that occurs is 145 L