A car moves along an x axis through a distance of 900 m, starting at rest (at x = 0) and ending at rest (at x = 900 m). Through the first 1/4 of that distance, its acceleration is +6.25 m/s2. Through the next 3/4 of that distance, its acceleration is -2.08 m/s2. What are (a) its travel time through the 900 m and (b) its maximum speed?
<span>Solve for the time at the 1/4 mark. That's 225 m. How? d = (1/2)at^2 ( initial velocity zero). Thus 225 = (1/2) 6.25 t^2. t^2 = ( 225 * 2 ) / 6.25. t = 8.5 sec. </span>
<span>At the other end t^2 = (675 * 2) / 2.08 -- we reversed the sign and ran time backwards. t = 25.5 sec. </span>
<span>So total time is 8.5 + 25.5 or 34 sec. </span>
<span>Since zero initial velocity: v^2 = 2 a d. Here, v^2 = 2 * 6.25 * 225. v = 53 m/s. That's the fastest speed since braking then occurs.</span>
Answer:
7056 kJ
Explanation:
Given that,
Mass of a ship roller coaster is 36,000 kg.
It reaches a height of 20 m off the ground
We need to find the gravitational potential energy does it have. The formula for the gravitational potential energy ios given by :
E = mgh
g is acceleration due to gravity
E = 36,000 kg × 9.8 m/s² × 20 m
= 7056000 J
or
E = 7056 kJ
So, it will have 7056 kJ of gravitational potential energy.
Answer:
Output voltage is 1.507 mV
Solution:
As per the question:
Nominal resistance, R = 
Fixed resistance, R =
Gauge Factor, G.F = 2.01
Supply Voltage, 
Strain, 
Now,
To calculate the output voltage, 
:
WE know that strain is given by:
Thus
Now, substituting the suitable values in the above eqn:
Wavelength = (speed) / (frequency)
= (30 m/s) / (60/sec) =
= 0.5 meter .
