Question

What is the specific heat (J/g⋅∘C) of a metal object whose temperature increases by 3.0∘C when 17.5 g of metal was heated with 38.5 J?

Answer 1

Answer:

0.733J/g°C

Explanation:

Using the formula

Q=mcΔθ

Q=38.5J, c=? , m=17.5g , Δθ=3°C

c= Q/(mΔθ)

$c=\frac{38.5}{17.5*3}$

c=0.733J/g°C