Answer:
The average velocity is
and respectively.
Explanation:
Let's start writing the vertical position equation :
Where distance is measured in meters and time in seconds.
The average velocity is equal to the position variation divided by the time variation.
= Δx / Δt =
For the first time interval :
t1 = 5 s → t2 = 8 s
The time variation is :
For the position variation we use the vertical position equation :
Δx = x2 - x1 = 1049 m - 251 m = 798 m
The average velocity for this interval is
For the second time interval :
t1 = 4 s → t2 = 9 s
Δx = x2 - x1 = 1495 m - 125 m = 1370 m
And the time variation is t2 - t1 = 9 s - 4 s = 5 s
The average velocity for this interval is :
Finally for the third time interval :
t1 = 1 s → t2 = 7 s
The time variation is t2 - t1 = 7 s - 1 s = 6 s
Then
The position variation is x2 - x1 = 701 m - (-1 m) = 702 m
The average velocity is
Answer:
85 Kg
314.041 N
Explanation:
We are given that
Mass of body on earth=85 kg
Acceleration due to gravity on earth=
Weight of body on earth=830 N
We have to find the mas of body and weight of body on Mars.
We know that mass of an object does not change with location .
It remain same everywhere.
Mass of body on Mars=85 kg
Gravitational acceleration on the surface of Mars=
We know that
Weight =
Using this formula
Weight of body=
Hence, the weight of body on Mars=314.041 N
Answer:
B. It can easily be transformed from high voltages to low voltages.
Explanation:
The distance should be 4m from the wire in order to get the magnetic field of 0.100μ .
- The magnitude and direction of the magnetic field due to a straight wire carrying current can be calculated using the previously mentioned Biot-Savart law. Let "I" be the current flowing in a straight line and "r" be the distance. Then the magnetic field produced by the wire at that particular point is given by ...(1)
- Since the wire is assumed to be very long, the magnitude of the magnetic field depends on the distance of the point from the wire rather than the position along the wire.
It is given that magnetic field 40.0 cm away from a straight wire is 1.00μT having current 2.00 A .
From equation (1) magnetic field 40.0 cm = 0.4m away from a straight wire is 1.00μT which is given by .....(2)
From equation (1) magnetic field 'r' m away from a straight wire is 0.100μT which is given by ...(3)
On dividing equation (2) by (3) , we get
Learn more about magnetic field here :
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Answer:
Columns of the periodic table are called groups.