law of conservation of mechanical energy
PE1 = Ek2
mgh=1/2mv²
h = 12 sin 60
Answer:
Explanation:
We are given that
r=2 in when t=4 s
We have to find the rate of change of radius.
We know that
Volume of sphere=
Differentiate w.r.t t
Substitute the values
Explanation:
Ohm's law describes the relationship between voltage, current, and resistance.
V = IR
where V is voltage, I is current, and R is resistance.
A. At the original voltage:
V₁ = I₁ R₁
When the voltage is doubled and resistance stays the same:
2V₁ = I₁' R₁
Dividing the two equations:
2V₁ / V₁ = (I₁' / I₁) (R₁ / R₁)
2 = I₁' / I₁
So the new current is double the original current.
B. At the original voltage and resistance:
V₂ = I₂ R₂
When both the voltage and resistance are increased by a factor of 2:
2V₂ = I₂' (2R₂)
Dividing the two equations:
(2V₂ / V₂) = (I₂' / I₂) (2R₂ / R₂)
2 = (I₂' / I₂) (2)
1 = I₂' / I₂
So the new current is the same as the original current.
Answer:
²₁H + ³₂He —> ⁴₂He + ¹₁H
Explanation:
From the question given above,
²₁H + ³₂He —> __ + ¹₁H
Let ⁿₐX be the unknown.
Thus the equation becomes:
²₁H + ³₂He —> ⁿₐX + ¹₁H
We shall determine, n, a and X. This can be obtained as follow:
For n:
2 + 3 = n + 1
5 = n + 1
Collect like terms
n = 5 – 1
n = 4
For a:
1 + 2 = a + 1
3 = a + 1
Collect like terms
a = 3 – 1
a = 2
For X:
n = 4
a = 2
X =?
ⁿₐX => ⁴₂X => ⁴₂He
Thus, the balanced equation is
²₁H + ³₂He —> ⁴₂He + ¹₁H
