At the bottom of a frictionless ramp, a 2kg mass reaches a speed of 9 m/s, how high is the top of the ramp? *
1 answer:
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Answer:
F = 41,954 N
Explanation:
given,
mass of bucket = 580 Kg
length of the cable = 20 m
velocity = 40 m/s
angle made = 38.0°
T cos 38° = m g..............(1)
T sin 38^0 = \dfrac{mv^2}{l} + F......(2)
dividing equation (2) by (1)
F = -46400 + 4445.36
F = -41,954 N
hence, the force is acting in the opposite direction as assumed.
F = 41,954 N