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SIZIF [17.4K]
2 years ago
6

At the bottom of a frictionless ramp, a 2kg mass reaches a speed of 9 m/s, how high is the top of the ramp? *

Physics
1 answer:
noname [10]2 years ago
3 0
V=√(2gs)
9=√(2×9.8×s)
s=4.1m
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Answer:

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Explanation:

First, we have find the specific heat capacity of the unknown substance.

The heat gained by the substance is given by the formula:

H = m*c*(T2 - T1)

Where m = mass of the substance

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From the question:

H = 200J

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T2 = 240 K

Therefore:

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200 = 160 * c

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Using the same formula:

500 = 4 * 1.25 * (T2 - 200)

500 = 5 * (T2 - 200)

100 = T2 - 200

=> T2 = 100 + 200 = 300 K

The new final temperature of the unknown substance is 300K.

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