Ask question

Ask question

All categories

3 years ago

8

Define the term potential energy of a body? How is it measured

2 answers:

kondaur [170]3 years ago

7 0

Answer:

The energy possessed by a body as a result of its position or condition rather than its motion.

Simplified, this formula can be written as: Potential Energy = mgh, where m is the mass, measured in kilograms; g is the acceleration due to gravity (9.8 m/s^2 at the surface of the Earth); and h is the height, measured in meters.

DENIUS [597]3 years ago

4 0

Answer:

potential energy. noun. the energy of a body or system as a result of its position in an electric, magnetic, or gravitational field. It is measured in joules (SI units), electronvolts, ergs, etcSymbol: E p, V, U, φ Abbreviation: PE.

Explanation:

You might be interested in

A bird is flying north with a mass of 2.5kg has a momentum of 17.5kg m/s at what velocity is it flying

klasskru [66]

Momentum = mass • velocity
v= 17.5/2.5
= 7 m/s

8 0

3 years ago

Read 2 more answers

Calcula la resistencia atravesada por una corriente con una intensidad de

Reil [10]

Hhhgcfghhhhhhhhhhhhhgh

5 0

3 years ago

If the box weighs 40 newtons and is lifted a distance of 2 meters, how much work is done on the box?

Zarrin [17]

Answer:

The work done on the box is 80 J.

Explanation:

Given that,

Weight of box = 40 N

Distance = 2 meter

We need to calculate the work done

Using formula of work done

$W=F\times x$

$W=mg\times x$

Where, x = distance

mg = weight

Put the value into the formula

$W=40\times2$

$W= 80\ Nm$

$W=80\ J$

Hence, The work done on the box is 80 J.

5 0

3 years ago

A photon with an energy E = 2.12 GeV creates a proton-antiproton pair in which the proton has a kinetic energy of 96.0 MeV. What

Oksanka [162]

Answer:

The kinetic energy of the anti proton is 147.4 MeV.

Explanation:

Given that,

Energy = 2.12 GeV

Kinetic energy = 96.0 MeV

We need to calculate the kinetic energy of the anti proton

Using formula of energy

$E_{photon}=m_{p}c^2+m_{np}c^2+K.E_{p}+K.E_{np}$

We know that,

$m_{p}c^2=m_{np}c^2$

So, $E_{photon}=2mc^2+K.E_{p}+K.E_{np}$

$K.E_{np}=E_{photon}-(2mc^2+K.E_{p})$

Put the value into the formula

$K.E_{np}=2.12\times10^{9}-2\times938.3\times10^{6}-96\times10^{6}$

$K.E_{np}=147.4\ MeV$

Hence, The kinetic energy of the anti proton is 147.4 MeV.

6 0

3 years ago

What is the rate of energy transferred

Elenna [48]

Answer:

Power is the rate of transfer of energy between energy stores.

Explanation:

6 0

3 years ago