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3 years ago

8

Define the term potential energy of a body? How is it measured

2 answers:

kondaur [170]3 years ago

7 0

Answer:

The energy possessed by a body as a result of its position or condition rather than its motion.

Simplified, this formula can be written as: Potential Energy = mgh, where m is the mass, measured in kilograms; g is the acceleration due to gravity (9.8 m/s^2 at the surface of the Earth); and h is the height, measured in meters.

DENIUS [597]3 years ago

4 0

Answer:

potential energy. noun. the energy of a body or system as a result of its position in an electric, magnetic, or gravitational field. It is measured in joules (SI units), electronvolts, ergs, etcSymbol: E p, V, U, φ Abbreviation: PE.

Explanation:

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A Ca atom (atomic number = 20) is in the ground state. Light is shined on the atom, exciting the most energetic electron. Which

Vikentia [17]

Answer:

The possible quantum numbers for Ca atom when it is in excited

n = 4

l= 1

m =-1,0,1

Explanation:

Given that,

Atomic number = 20

The configuration of Ca

$Ca = 1s^2 2s^2 2p^6 3s^2 3p^6 4s^2$

So, The principle quantum number is n =4.

The azimuthal quantum number can take value from 0,1,2...(n-1)

In the ground state, l= 0

When it is excited to p state

Then, l = 1

The magnetic quantum number can take value from l to -l

$m=1,0,-1$

Hence, The possible quantum numbers for Ca atom when it is in excited

n = 4

l= 1

m =-1,0,1

4 0

3 years ago

A particle with charge 7.76×10^(−8)C is moving in a region where there is a uniform 0.700 T magnetic field in the +x-direction.

kodGreya [7K]

Answer:

The z-component of the force is $\= F_z = 0.00141 \ N$

Explanation:

From the question we are told that

The charge on the particle is $q = 7.76 *0^{-8} \ C$

The magnitude of the magnetic field is $B = 0.700\r i \ T$

The velocity of the particle toward the x-direction is $v_x = -1.68*10^{4}\r i \ m/s$

The velocity of the particle toward the y-direction is

$v_y = -2.61*10^{4}\ \r j \ m/s$

The velocity of the particle toward the z-direction is

$v_y = -5.85*10^{4}\ \r k \ m/s$

Generally the force on this particle is mathematically represented as

$\= F = q (\= v X \= B )$

So we have

$\= F = q ( v_x \r i + v_y \r j + v_z \r k ) \ \ X \ ( \= B i)$

$\= F = q (v_y B(-\r k) + v_z B\r j)$

substituting values

$\= F = (7.7 *10^{-8})([ (-2.61*10^{4}) (0.700)](-\r z) + [(5.58*10^{4}) (0.700)]\r y)$

$\= F= 0.00303\ \r j +0.00141\ \r k$

So the z-component of the force is $\= F_z = 0.00141 \ N$

Note : The cross-multiplication template of unit vectors is shown on the first uploaded image ( From Wikibooks ).

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3 years ago

At which point is the kinetic energy the greatest?

pshichka [43]

Answer:

X

Explanation:

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3 years ago

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Semmy [17]

Answer:

0

Explanation:

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2 years ago

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scoundrel [369]

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3 years ago