Answer:
Se the explanation below
Explanation:
We do not feel these forces of these bodies, because they are very small compared to the force of Earth's attraction. Although its mass is greater than that of a human being, its mass is not compared to the Earth's mass. In order to understand this problem we will use numerical data and the universal gravitation formula, to give validity to the explanation.
<u>Force exerted by the Earth on a human being</u>
<u />
Where:
G = universal gravitation constant = 6.673*10^-11 [N*m^2/kg^2]
m1 = mass of the person = 80 [kg]
m2 = mass of the earth 5.97*10^24[kg]
r = distance from the center of the earth to the surface or earth radius = 6371 *10^3 [m]
<u />
Now replacing we have
![F = 6.673*10^{-11} *\frac{80*5.97*10^{24}}{(6371*10^{3})^{2} } \\F = 785[N]](https://tex.z-dn.net/?f=F%20%3D%206.673%2A10%5E%7B-11%7D%20%2A%5Cfrac%7B80%2A5.97%2A10%5E%7B24%7D%7D%7B%286371%2A10%5E%7B3%7D%29%5E%7B2%7D%20%20%7D%20%5C%5CF%20%3D%20785%5BN%5D)
<u>Force exerted by a building on a human being</u>
<u />
Where:
G = universal gravitation constant = 6.673*10^-11 [N*m^2/kg^2]
m1 = mass of the person = 80 [kg]
m2 = mass of the earth 300000 [ton] = 300 *10^6[kg]
r = distance from the building to the person = 2[m]
![F = 6.673*10^{-11}*\frac{80*300*10^6}{2^{2} } \\F= 0.4 [N]](https://tex.z-dn.net/?f=F%20%3D%206.673%2A10%5E%7B-11%7D%2A%5Cfrac%7B80%2A300%2A10%5E6%7D%7B2%5E%7B2%7D%20%7D%20%20%5C%5CF%3D%200.4%20%5BN%5D)
As we can see the force exerted by the Earth is 2000 times greater than that exerted by a building with the proposed data.
Answer:
θ = θ₀ + ½ w₀ (t -t_1) + α (t -t_1)²
Explanation:
This is an angular kinematic exercise the equation for the angular position
the particle A
θ = θ₀ + ω₀ t + ½ α t²
They say for the particle B
w₀B = ½ w₀
αB = 2 α
In addition, the particle begins at a time t_1 after particle A, in order to use the same timer, we must subtract this time from the initial
t´ = t - t_1
l
et's write the equation of particle B
θ = θ₀ + w₀B t´ + ½ αB t´2
replace
θ = θ₀ + ½ w₀ (t -t_1) + ½ 2α (t -t_1)²
θ = θ₀ + ½ w₀ (t -t_1) + α (t -t_1)²
Answer:
(3) 690 N
Explanation:
Force: This is the product of mass and acceleration of a body. The S.I unit of force is Newton(N).
The formula for force is given as,
F = ma..................... Equation 1
Where F = force, m = mass, a = acceleration.
Also,
a = (v-u)/t................... Equation 2
Where v = Final velocity, u = initial velocity, t = time.
Given: u = 6.0 m/s, v = 0 m/s (bring to stop), t = 0.65 s.
Substitute into equation 2
a = (0-6)/0.65
a = -6/0.65
a = -9.23 m/s²
Also given: m = 75 kg
Substitute again into equation 1
F = 75(-9.23)
F = -692.25 N
The negative sign tells that the force oppose the motion of the player
F ≈ 690 N
Hence the right option is (3) 690 N
Answer:
D strengths and weakneses
Explanation:
I believe the answer is D. <span>The hypothesis is revised and another experiment is conducted.</span>
