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enyata [817]
3 years ago
12

How much heat is released when 12.0 grams of helium gas condense at 2.17 K? The latent heat of vaporization of helium is 21 J/g.

Physics
2 answers:
uranmaximum [27]3 years ago
8 0
To determine the heat released by the process of condensation, we simply multiply the amount of the gas that condensed to the latent heat of vaporization. We do as follows:

Heat released = 21 J/g (12.0 g ) = 252 J of heat released
Alisiya [41]3 years ago
4 0

The correct answer is -250 J.

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A 2.40 μC charge is subject to a 3.00 mN force due to an Electric Field. What is the magnitude of the Electric Field at the loca
Bezzdna [24]
<h2>Electric field at the location of the charge is 1250 N/C</h2>

Explanation:

Electric field is the ratio of force and charge.

Force, F = 3.00 mN = 3 x 10⁻³ N

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We have

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Which statement about projectile motion is true?
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C. The range of a projectile increases with an increase in the angle of launch.

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Modern atomic theory states that atoms are neutral. how is this neutrality achieved in atoms? having more neutrons than protons
kolezko [41]
The answer is having fewer neutrons than protons or electrons.
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4 years ago
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The planet Mars has a mass of 6.1 × 1023 kg and radius of 3.4 × 106 m. What is the acceleration of an object in free fall near t
Oksanka [162]

The acceleration due to gravity of Mars is 3.5\ m / s^{2}

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As per universal law of gravity, the gravitational force is directly proportional to the product of masses and inversely proportional to the square of the distance between them. But in the present case, the gravity need to be determined between Mars and the object on Mars. Since the mass of Mars is greater than the mass of any object. Thus,

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Also, according to Newton’s second law of motion, the acceleration of any object will be equal to the ratio of force exerted on it to the mass of the object.

So in order to determine the acceleration due to gravity of Mars, divide the gravitational force of Mars by mass of object on the surface of Mars.

   Acceleration\ due\ to\ gravity\ of\ mars =\frac{\text {Gravitational force of Mars}}{m \text { of object }}

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3 0
3 years ago
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3 years ago
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