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enyata [817]
3 years ago
12

How much heat is released when 12.0 grams of helium gas condense at 2.17 K? The latent heat of vaporization of helium is 21 J/g.

Physics
2 answers:
uranmaximum [27]3 years ago
8 0
To determine the heat released by the process of condensation, we simply multiply the amount of the gas that condensed to the latent heat of vaporization. We do as follows:

Heat released = 21 J/g (12.0 g ) = 252 J of heat released
Alisiya [41]3 years ago
4 0

The correct answer is -250 J.

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Answer:

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and

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a =  \frac{0.67\times 1.6\times 10^{-19}\times 3.25\times 10^7}{9.1\times 10^{-31}}

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and

electron moving in circular orbit has centripetal force

F = \frac{mv^2}{r}  

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r = \frac{9.1\times 10^{-31}\times 3.25\times 10^7}{0.67\times 1.6\times 10^{-19}}  

r = 2.76 × 10^{-4} m

radius of circular orbit is 2.76 × 10^{-4} m

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