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Readme [11.4K]
3 years ago
5

Basidiomycete fungi ballistically eject millions of spores into the air by releasing the surface tension energy of a water dropl

et condensing on the spore. The spores are ejected with typical speeds of 1.09 m/s, allowing them to clear the "boundary layer" of still air near the ground to be carried away and dispersed by winds.
(a) If a given spore is accelerated from rest to 1.09 m/s in 7.85 µs, what is the magnitude of the constant acceleration of the spore (in m/s^2) while being ejected?
Physics
1 answer:
GalinKa [24]3 years ago
6 0

Answer:

1.4 x 10^5 m/s^2.

Explanation:

Given the following:

vi = 0 m/s.

vf = 1.09 m/s.

t = 7.85 µs.

Using,

vf = vi + a*t

1.09 = a*7.8 x 10^-6

a = 139743.6

= 1.4 x 10^5 m/s^2.

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Please hurry Describe why electric currents can be dangerous
konstantin123 [22]

Answer:

Cardiac Arrest, burns, and nerve damage.

Explanation:

Basically, the main risk is cardiac arrest, caused by the electric current interfering with the normal operation of the heart muscle. Other possible damages are burns due to the electric energy vaporizing the water inside the cells, and nerve damage caused by excessive current through the nerves.

7 0
3 years ago
A circular curve of radius 150 m is banked at an angle of 15 degrees. A 750-kg car negotiates the curve at 85.0 km/h without ski
Crazy boy [7]

Answer: a) 7.1 * 10^3 N; b) -880 N directed out of the curve.

Explanation: In order to solve this problem we have to use the Newton laws, then we have the following:

Pcos 15°-N=0

Psin15°-f= m*ac

from the first we obtain N, the normal force

N=750Kg*9.8* cos (15°)= 7.1 *10^3 N

Then to calculate the frictional force (f) we can use the second equation

f=P sin (15°) -m*ac where ac is the centripetal acceletarion which is equal to v^2/r

f= 750 *9.8 sin(15°)-750*(85*1000/3600)^2/150= -880 N

6 0
3 years ago
What is the mechanical advantage of a lever that has an input arm of 6 meters and an output arm of 2 meters
Setler79 [48]

Answer:A

Explanation:I TOOK THE Test

5 0
3 years ago
Sound is repeated near hills.​why
Anon25 [30]

Answer:

Sound waves are reflected back

5 0
3 years ago
a cone is constructed by cutting a sector from a circular sheet of metal with radius . the cut sheet is then folded up and welde
Svet_ta [14]

The expression for the radius and height of the cone can be obtained from

the property of a function at the maximum point.

  • The \ radius, \ of \ the \ base \ of \ the \ cone \ is \ \sqrt{ \dfrac{3}{4}} \times radius \ of \ circular \ sheet \ metal
  • The height of the cone is half the length of the radius of the circular sheet metal.

Reasons:

The part used to form the cone = A sector of a circle

The length of the arc of the sector = The perimeter of the circle formed by the base of the cone.

Volume \ of \ a \ cone = \dfrac{1}{3} \cdot  \pi \cdot r^3 \cdot h

  • Volume \ of \ a \ cone, \, V = \dfrac{1}{3} \cdot  \pi \cdot r^3 \cdot \sqrt{(s^2- r^2)}

θ/360·2·π·s = 2·π·r

Where;

s = The radius of he circular sheet metal

h = s² - r²

  • \dfrac{dV}{dr} = \dfrac{d}{dr}  \left(\dfrac{1}{3} \cdot  \pi \cdot r^3 \cdot \sqrt{(s^2- r^2)}\right) = \dfrac{\pi \cdot (3 \cdot r^2 \cdot  s^2 - 4 \cdot r^4)}{\sqrt{(s^2- r^2)}} = 0

3·r²·s² - 4·r⁴ = 0

3·r²·s² = 4·r⁴

3·s² = 4·r²

\underline{\left  \right. The \ radius, \, r =\sqrt{ \dfrac{3}{4}} \cdot s}

\underline{The \ height, \, h =\sqrt{s^2 - \dfrac{3}{4}\cdot s^2} = \dfrac{s}{2}}}

Learn more here:

brainly.com/question/14466080

3 0
3 years ago
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