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Readme [11.4K]
3 years ago
5

Basidiomycete fungi ballistically eject millions of spores into the air by releasing the surface tension energy of a water dropl

et condensing on the spore. The spores are ejected with typical speeds of 1.09 m/s, allowing them to clear the "boundary layer" of still air near the ground to be carried away and dispersed by winds.
(a) If a given spore is accelerated from rest to 1.09 m/s in 7.85 µs, what is the magnitude of the constant acceleration of the spore (in m/s^2) while being ejected?
Physics
1 answer:
GalinKa [24]3 years ago
6 0

Answer:

1.4 x 10^5 m/s^2.

Explanation:

Given the following:

vi = 0 m/s.

vf = 1.09 m/s.

t = 7.85 µs.

Using,

vf = vi + a*t

1.09 = a*7.8 x 10^-6

a = 139743.6

= 1.4 x 10^5 m/s^2.

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The belief that scientific psychology should be studying only observable behaviors is known as __________.
kifflom [539]

BEHAVIOURISM holds the belief that scientific psychology should be studying only obserrvable behaviors. The underlying principle of behaviourism is that behavior is influenced by our interaction with the environment and has little to do with factors internal to us. From which follows the assumption that when we are born, our mind is a blank slate

4 0
3 years ago
Read 2 more answers
A ball is thrown straight up at 20 m. What is the balls velocity as it hits the ground?
deff fn [24]

Answer:

<em>The velocity of the ball as it hit the ground = 19.799 m/s</em>

Explanation:

Velocity: Velocity of a body can be defined as the rate of change of displacement of the body. The S.I unit of velocity is m/s. velocity is expressed in one of newtons equation of motion, and is given below.

v² = u² + 2gs.......................... Equation 1

Where v = the final velocity of the ball, g = acceleration due to gravity, s = the height of the ball

<em>Given: s = 20 m, u = 0 m/s</em>

<em>Constant: g = 9.8 m/s²</em>

<em>Substituting these values into equation 1,</em>

<em>v² = 0 + 2×9.8×20</em>

<em>v² = 392</em>

<em>v = √392</em>

<em>v = 19.799 m/s.</em>

<em>Therefore the velocity of the ball as it hit the ground = 19.799 m/s</em>

5 0
3 years ago
A gymnast of mass 62.0 kg hangs from a vertical rope attached to the ceiling. You can ignore the weight of the rope and assume t
MrRissso [65]

Answer:

a) T = 608.22 N

b) T = 608.22 N

c) T = 682.62 N

d) T = 533.82 N

Explanation:

Given that the mass of gymnast is m = 62.0 kg

Acceleration due to gravity is g = 9.81 m/s²

Thus; The weight of the gymnast is acting downwards and tension in the string acting upwards.

So;

To calculate the tension T in the rope if the gymnast hangs motionless on the rope; we have;

T = mg

= (62.0 kg)(9.81 m/s²)

= 608.22 N

When the gymnast climbs the rope at a constant rate tension in the string is

= (62.0 kg)(9.81 m/s²)

= 608.22 N

When the gymnast climbs up the rope with an upward acceleration of magnitude

a = 1.2 m/s²

the tension in the string is  T - mg = ma (Since acceleration a is upwards)

T = ma + mg

= m (a + g )

= (62.0 kg)(9.81 m/s² + 1.2  m/s²)

= (62.0 kg) (11.01 m/s²)

= 682.62 N

When the gymnast climbs up the rope with an downward acceleration of magnitude

a = 1.2 m/s² the tension in the string is  mg - T = ma (Since acceleration a is downwards)

T = mg - ma

= m (g - a )

= (62.0 kg)(9.81 m/s² - 1.2 m/s²)

= (62.0 kg)(8.61 m/s²)

= 533.82 N

5 0
3 years ago
What is the kinetic energy of a 1,350kg car traveling at a speed of 12m/s?
Ainat [17]
Kinetic energy= 1/2 m v^2

so... 1/2(1350)(12^2)

kinetic energy = 97200Joules
7 0
3 years ago
~choices below~
mart [117]
A is the correct answer
5 0
3 years ago
Read 2 more answers
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