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Readme [11.4K]
2 years ago
5

Basidiomycete fungi ballistically eject millions of spores into the air by releasing the surface tension energy of a water dropl

et condensing on the spore. The spores are ejected with typical speeds of 1.09 m/s, allowing them to clear the "boundary layer" of still air near the ground to be carried away and dispersed by winds.
(a) If a given spore is accelerated from rest to 1.09 m/s in 7.85 µs, what is the magnitude of the constant acceleration of the spore (in m/s^2) while being ejected?
Physics
1 answer:
GalinKa [24]2 years ago
6 0

Answer:

1.4 x 10^5 m/s^2.

Explanation:

Given the following:

vi = 0 m/s.

vf = 1.09 m/s.

t = 7.85 µs.

Using,

vf = vi + a*t

1.09 = a*7.8 x 10^-6

a = 139743.6

= 1.4 x 10^5 m/s^2.

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An external resistor with resistance R is connected to a battery that has an emf E and an internal resistance r. Let P be the el
satela [25.4K]

Answer:

a) When R is very small R << r, therefore the term R+ r will equal r and the current becomes  

b) When R is very large, R >> r, therefore the term R+ r will equal R and the current becomes

Explanation:

<u>Solution  :</u>

(a) We want to get the consumed power P when R is very small. The resistor in the circuit consumed the power from this battery. In this case, the current I is leaving the source at the higher-potential terminal and the energy is being delivered to the external circuit where the rate (power) of this transfer is given by equation  in the next form  

P=∈*I-I^2*r                (1)

Where the term ∈*I is the rate at which work is done by the battery and the term I^2*r is the rate at which electrical energy is dissipated in the internal resistance of the battery. The current in the circuit depends on the internal resistance r and we can apply equation to get the current by  

I=∈/R+r                     (2)

When R is very small R << r, therefore the term R+ r will equal r and the current becomes  

I= ∈/r

Now let us plug this expression of I into equation (1) to get the consumed power  

P=∈*I-I^2*r

 =I(∈-I*r)

 =0

The consumed power when R is very small is zero  

(b) When R is very large, R >> r, therefore the term R+ r will equal R and the current becomes  

I=∈/R

The dissipated power due toll could be calculated by using equation.

P=I^2*r                (3)

Now let us plug the expression of I into equation (3) to get P  

P=I^2*R=(∈/R)^2*R

 =∈^2/R

4 0
3 years ago
One way for a family to determine their energy use is by analyzing their electric bill each month. Most energy bills include a g
strojnjashka [21]

Answer:

C)Before leaving for their trip, turn the central heating system off, along with lights and electrical household appliances.

Explanation:

Although, the other three options will also reduce their electricity bill but they do not explain why Mr. Hernandez's family got same electricity bill as last year even though this time they were not home for one and a half week. Also, A), B) and D) ideas are not reasonable.

So, the only conclusion is that even when they were on a vacation. the electrical appliances in their home were on. That's why the bill remained the same.

The idea of turning the central heating system off, along with lights and electrical household appliances before they leave for the trip will help reduce the energy usage. Also, it is reasonable.

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The left hemisphere of the brain is responsible for language and speech
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Explanation:

Not given answer choices, but this is efficient as energy is taken from the sun.

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A roller coaster uses the track in this picture. Where will the roller coaster have the
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