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2 years ago

11

Mark is cutting construction paper into rectangles for a project. He needs to cut one rectangle that is 12 inches × 13 1/3 inche

s. He needs to cut another rectangle that is 10 1/4 inches x 10 1/3 inches
How many total square inches of construction paper does Mark need for his project?
PLS I NEED TO GO TO SCHOOL PLS

1 answer:

Anna11 [10]2 years ago

4 0

Answer: 265.9167 square inches (rounded)

Step-by-step explanation:

Shoot, okay if this is wrong, shame on me:

All you do is find the areas of each rectangle and add them together.

(12 × 13 1/3) + (10 1/4 x 10 1/3) = 265.9167 (rounded) square inches. Or as a fraction: 3191/12

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Convert 3 and 19/20 to a decimal

inysia [295]

3 is converted to 0.03
19/20 is converted to 0.95.

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2 years ago

In simplified exponential notation, the expression x ³ · x -4 · x =

Ivan

X^3 * x^2 - 4 is your answer. Hope this helps!

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2 years ago

which equations are equivalent to 3/4+m=-7/4 check all that apply m=10/4 m=-10/4 m=-5/2 11/4+m=-1/4 -5/4+m=-15/4 m+2=-0.5 Help f

Alecsey [184]

Answer:

The correct choices are; B,C,E, and F.

Step-by-step explanation:

The given equation is;

$\frac{3}{4}+m=-\frac{7}{4}$

We solve for m to obtain:

$m=-\frac{7}{4}-\frac{3}{4}=-2.5$

We also solve the remaining equations to see which ones give the same result.

A: $m=\frac{10}{4} =2.5$

B: $m=-\frac{10}{4} =-2.5$

C: $m=-\frac{5}{2} =-2.5$

D: $\frac{11}{4}+m=-\frac{1}{4}$

$m=-\frac{1}{4}-\frac{11}{4}=-3$

E: $-\frac{5}{4}+m=-\frac{15}{4}$

$m=-\frac{15}{4}+\frac{5}{4}=-2.5$

F: $m+2=-0.5$

$m=-0.5-2=-2.5$

The equivalent equations are; B,C,E, and F.

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2 years ago

Read 2 more answers

Factor the polynomial, x2 + 5x + 6

patriot [66]

Answer:

Choice b.

$x^{2} + 5\, x + 6 = (x + 3)\, (x + 2)$ .

Step-by-step explanation:

The highest power of the variable $x$ in this polynomial is $2$ . In other words, this polynomial is quadratic.

It is thus possible to apply the quadratic formula to find the "roots" of this polynomial. (A root of a polynomial is a value of the variable that would set the polynomial to $0$ .)

After finding these roots, it would be possible to factorize this polynomial using the Factor Theorem.

Apply the quadratic formula to find the two roots that would set this quadratic polynomial to $0$ . The discriminant of this polynomial is $(5^{2} - 4 \times 1 \times 6) = 1$ .

$\begin{aligned}x_{1} &= \frac{-5 + \sqrt{1}}{2\times 1} \\ &= \frac{-5 + 1}{2} \\ &= -2\end{aligned}$ .

Similarly:

$\begin{aligned}x_{2} &= \frac{-5 - \sqrt{1}}{2\times 1} \\ &= \frac{-5 - 1}{2} \\ &= -3\end{aligned}$ .

By the Factor Theorem, if $x = x_{0}$ is a root of a polynomial, then $(x - x_0)$ would be a factor of that polynomial. Note the minus sign between $x$ and $x_{0}$ .

The root $x = -2$ corresponds to the factor $(x - (-2))$ , which simplifies to $(x + 2)$ .
The root $x = -3$ corresponds to the factor $(x - (-3))$ , which simplifies to $(x + 3)$ .

Verify that $(x + 2)\, (x + 3)$ indeed expands to the original polynomial:

$\begin{aligned}& (x + 2)\, (x + 3) \\ =\; & x^{2} + 2\, x + 3\, x + 6 \\ =\; & x^{2} + 5\, x + 6\end{aligned}$ .

4 0

2 years ago

10. A 266-hp output is required for an engine. If there is a 5% loss of power, what amount of input

marta [7]

Answer:

Amount of input horsepower needed is 279.3 hp.

Step-by-step explanation:

if there is a loss of power of 5% the base horsepower will need to be increased by same percentage so that same amount of power can be delivered.

Now to calculate 5% of 266 hp, we can write

266 × $\frac{5}{100}$ = 13.3 hp

Now to deliver same amount of power we will have to add 5% of 266 hp to its actual power.

So real base power which is needed to deliver 266hp output even at a loss of 5% will be = (266+13.3) hp = 279.3 hp

To know more about horsepower and percentage problem:

brainly.com/question/24585630

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2 years ago