The given expression is:
![10-3\sqrt{1.21}](https://tex.z-dn.net/?f=%2010-3%5Csqrt%7B1.21%7D%20%20)
Now, we know that the square of 1.1 is 1.21, which means that 1.1 multiplied by itself gives 1.21.
Mathematically, that can be expressed as:
![1.1\times 1.1=1.21](https://tex.z-dn.net/?f=%201.1%5Ctimes%201.1%3D1.21%20)
or, ![(1.1)^2=1.21](https://tex.z-dn.net/?f=%20%281.1%29%5E2%3D1.21%20)
thus, the square root of 1.21 is 1.1
or ![\sqrt{1.21}=1.1](https://tex.z-dn.net/?f=%20%5Csqrt%7B1.21%7D%3D1.1%20%20)
Thus, applying this in the expression in the question given to us, we will get:
![10-3\sqrt{1.21}=10-3\times 1.1=10-3.3=6.7](https://tex.z-dn.net/?f=%2010-3%5Csqrt%7B1.21%7D%3D10-3%5Ctimes%201.1%3D10-3.3%3D6.7%20%20)
Thus, 6.7 is the final answer for the given expression.
Answer:
<h3>p = 131.25</h3>
Step-by-step explanation:
The variation p varies directly with T is written as
p = kT
where k is the constant of proportionality
To find p when T =500 we must first find the formula for the variation
That's
when p = 105 and T = 400
105 = 400k
Divide both sides by 400
<h3>
![k = \frac{21}{80}](https://tex.z-dn.net/?f=k%20%3D%20%20%5Cfrac%7B21%7D%7B80%7D%20)
</h3>
So the formula for the variation is
<h2>
![p = \frac{21}{80} T](https://tex.z-dn.net/?f=p%20%3D%20%20%5Cfrac%7B21%7D%7B80%7D%20T)
</h2>
when
T = 500
Substitute it into the above formula
That's
![p = \frac{21}{80} \times 500](https://tex.z-dn.net/?f=p%20%3D%20%20%5Cfrac%7B21%7D%7B80%7D%20%20%5Ctimes%20500)
Simplify
The final answer is
<h3>p = 131.25</h3>
Hope this helps you
Answer:
yes 6 is great answr\er
Step-by-step explanation:
Answer:
a₇₆ = - 134
Step-by-step explanation:
The n th term of an arithmetic sequence is
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Here a₁ = 16 and d = a₂ - a₁ = 14 - 16 = - 2, then
a₇₆ = 16 + (75 × - 2) = 16 - 150 = - 134
5w - 10 > 20
5w > 20 + 10
5w > 30
w > 30/5
w > 6
Answer: 7, 8.