The sum of three consecutive integers is three times the middle one: if we call the middle one , the three numbers are
So, their sum is
Which is three times the middle one.
So, if the sum of three consecutive intergers is 48, the middle one must be 48/3 = 16.
So, the three numbers are 15, 16 and 17
Answer: 484
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Work Shown:
First let's compute f(2). We replace every x with 2 and then use PEMDAS to simplify
f(x) = -x^4 + 5x - 4x^2
f(2) = -(2)^4 + 5(2) - 4(2)^2
f(2) = -16 + 5(2) - 4(4)
f(2) = -16 + 10 - 16
f(2) = -6 - 16
f(2) = -22
Then we square this result to find the value of