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pav-90 [236]
3 years ago
9

Convert 3.8 kg to Lbs

Physics
2 answers:
JulijaS [17]3 years ago
8 0
I believe it’s 8.3 to be precise
Ray Of Light [21]3 years ago
3 0

Answer:

8.37757

Explanation:

may i have brainliest

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Non examples of convert
german

Answer:

another. persist. continue. last. remain.

Explanation:

8 0
2 years ago
Question #10. A rock is white in color, when viewed in sunlight.. In a windowless room, red light is shined on the rock. What co
likoan [24]

We will have the following:

Since it is a white rock, then when in a windowless room with just red light the color that will appear to our eyes is red. Since is the only color to reflect.

5 0
1 year ago
Which of the following states that absolute zero cannot be reached?
olganol [36]
The second and third laws of thermodynamics states that absolute zero cannot be reached. The correct option among all the options that are given in the question is the third option or option "C". Both the laws actually deal with the relations that exist between heat and other forms of energy. I hope the answer helps you.
4 0
3 years ago
Read 2 more answers
The specific heat capacity of ethanol is 2440J/kg °C. How many joules of energy will be required to heat 150g ethanol to 35°C if
m_a_m_a [10]

Answer:

Required energy = 4758 J

Explanation:

Specific heat capacity of a material is the amount of energy required to raise the temperature of one kilogram (kg) of that material through one degree Celsius (°C).    

Given data :

Specific heat capacity = c = 2440 J/kg.°C

Mass = m = 150 g = 0.15 kg

Initial temperature = 22°C

Final temperature = 35°C

Change in Temperature = ΔT = 13°C

Energy = E = ?

Using the following formula and substituting the values, we get:

E = m × c × ΔT

E = 0.15 × 2440 × 13

E = 4758 J

8 0
3 years ago
The pressure in a compressed air storage tank is 1200 kPa. What is the tank’s pressure in (a) kN and m units; (b) kg, m, and s u
elixir [45]

Explanation:

Given data

Pressure P=1200 kPa

To find

Pressure in

(a) kN/m²

(b) kg/m.s²

(c) kg/km.s²

Solution

For Part (a)

P=(1200kPa)(\frac{1kN/m^{2} }{1kPa} )\\P=1200kN/m^{2}

For Part (b)

P=(1200kPa)(\frac{1kN/m^{2} }{1kPa} )(\frac{1000kg.m/s^{2} }{1kN} )\\P=1,200,000kg/m.s^{2}

For Part (c)

P=(1200kPa)(\frac{1kN/m^{2} }{1kPa} )(\frac{1000kg.m/s^{2} }{1kN} )(\frac{100m}{1km} )\\P=1,200,000,000kg/km.s^{2}

8 0
4 years ago
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