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melamori03 [73]
3 years ago
6

A frictionless pendulum clock on the surface of the earth has a period of 1.00 s. On a distant planet, the length of the pendulu

m must be shortened slightly to have a period of 1.00 s. What is true about the acceleration due to gravity on the distant planet?
Physics
1 answer:
Marianna [84]3 years ago
3 0

Answer:

The acceleration due to gravity on the other planet is less than the acceleration due to gravity on Earth

Explanation:

The time period of a pendulum is given by

T=2\pi\sqrt{\frac{L}{g}}

where,

L = Length of the pendulum

g = Acceleration due to gravity

It can be seen that the time is proportional to the length and inversely proportional to the acceleration due to gravity. So, if L is reduced to keep the same time period then g must be also less.

Hence, the acceleration due to gravity on the other planet is less than the acceleration due to gravity on Earth.

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An elastic conducting material is stretched into a circular loop of 9.65 cm radius. It is placed with its plane perpendicular to
Nadya [2.5K]

Answer:

The induced emf in the coil is 0.522 volts.                        

Explanation:

Given that,

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The radius of the loop starts to shrink at an instantaneous rate of 75.6 cm/s , \dfrac{dr}{dt}=-0.756\ m/s

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\epsilon=\dfrac{-d\phi}{dt}\\\\\epsilon=\dfrac{-d(BA)}{dt}\\\\\epsilon=B\dfrac{-d(\pi r^2)}{dt}\\\\\epsilon=2\pi rB\dfrac{dr}{dt}\\\\\epsilon=2\pi \times 9.65\times 10^{-2}\times 1.14\times 0.756\\\\\epsilon=0.522\ V

So, the induced emf in the coil is 0.522 volts.                                

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