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melamori03 [73]
3 years ago
6

A frictionless pendulum clock on the surface of the earth has a period of 1.00 s. On a distant planet, the length of the pendulu

m must be shortened slightly to have a period of 1.00 s. What is true about the acceleration due to gravity on the distant planet?
Physics
1 answer:
Marianna [84]3 years ago
3 0

Answer:

The acceleration due to gravity on the other planet is less than the acceleration due to gravity on Earth

Explanation:

The time period of a pendulum is given by

T=2\pi\sqrt{\frac{L}{g}}

where,

L = Length of the pendulum

g = Acceleration due to gravity

It can be seen that the time is proportional to the length and inversely proportional to the acceleration due to gravity. So, if L is reduced to keep the same time period then g must be also less.

Hence, the acceleration due to gravity on the other planet is less than the acceleration due to gravity on Earth.

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A 26-g steel-jacketed bullet is fired with a velocity of 630 m/s toward a steel plate and ricochets along path CD with a velocit
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  F = - 3.53 10⁵ N

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This problem must be solved using the relationship between momentum and the amount of movement.

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          m = 26 g ( 1 kg/1000g) = 26 10⁻³ kg

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As the bullet bounces the speed sign after the crash is negative

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