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melamori03 [73]
3 years ago
6

A frictionless pendulum clock on the surface of the earth has a period of 1.00 s. On a distant planet, the length of the pendulu

m must be shortened slightly to have a period of 1.00 s. What is true about the acceleration due to gravity on the distant planet?
Physics
1 answer:
Marianna [84]3 years ago
3 0

Answer:

The acceleration due to gravity on the other planet is less than the acceleration due to gravity on Earth

Explanation:

The time period of a pendulum is given by

T=2\pi\sqrt{\frac{L}{g}}

where,

L = Length of the pendulum

g = Acceleration due to gravity

It can be seen that the time is proportional to the length and inversely proportional to the acceleration due to gravity. So, if L is reduced to keep the same time period then g must be also less.

Hence, the acceleration due to gravity on the other planet is less than the acceleration due to gravity on Earth.

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Explanation:

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energy going to neutrino .

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An open organ pipe is 1.6m long. If the speed of sound is 343m/s, what are the pipes: a) fundamental , b) 1st overtone , & c
Yakvenalex [24]

Answer:

a) 107.1875 Hz

b) 214.375 Hz

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Explanation:

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f = \frac{v}{2L}

inserting the values

f = \frac{343}{2(1.6)}

f = \frac{343}{2(1.6)}

f = 107.1875 Hz

b)

first overtone is given as

f' = 2f

f' = 2 (107.1875)

f' = 214.375 Hz

c)

first overtone is given as

f'' = 3f

f'' = 3 (107.1875)

f'' = 321.5625 Hz

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ans 5

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hope it's help It seems to me

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