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melamori03 [73]
3 years ago
6

A frictionless pendulum clock on the surface of the earth has a period of 1.00 s. On a distant planet, the length of the pendulu

m must be shortened slightly to have a period of 1.00 s. What is true about the acceleration due to gravity on the distant planet?
Physics
1 answer:
Marianna [84]3 years ago
3 0

Answer:

The acceleration due to gravity on the other planet is less than the acceleration due to gravity on Earth

Explanation:

The time period of a pendulum is given by

T=2\pi\sqrt{\frac{L}{g}}

where,

L = Length of the pendulum

g = Acceleration due to gravity

It can be seen that the time is proportional to the length and inversely proportional to the acceleration due to gravity. So, if L is reduced to keep the same time period then g must be also less.

Hence, the acceleration due to gravity on the other planet is less than the acceleration due to gravity on Earth.

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A basketball is tossed upwards with a speed of 5.0 m/s. ​We can ignore air resistance.
FinnZ [79.3K]

We have that  the maximum height reached by the basketball from its release point is

S=1.3m

From the question we are told

  • A basketball is tossed upwards with a speed of 5.0 m/s. ​We can ignore air resistance.  
  • What is the maximum height reached by the basketball from its release point?

Generally the Newtons equation for Motion  is mathematically given as

V^2=u^2+2as\\\\Therefore\\\\0=25-19.6*S\\\\S=\frac{25}{19.6}\\\\S=1.276

S=1.3m

Therefore

The maximum height reached by the basketball from its release point is

S=1.3m

For more information on this visit

brainly.com/question/23366835

4 0
3 years ago
How does the eye and brain work together to give you perception of color
Nimfa-mama [501]

Answer:

The human eye and brain together translate light into color. Light receptors within the eye transmit messages to the brain, which produces the familiar sensations of color. ... Rather, the surface of an object reflects some colors and absorbs all the others. We perceive only the reflected colors.

Explanation:

8 0
3 years ago
If a rod attached to the approaching charge if the rod consists of "stiff" spring-like bonds for which atoms undergo small oscil
Hoochie [10]

Answer: hello options related to your question is missing attached below is the missing part of your question

answer: No charge of the length of the bonds expected because the rod did not touch the charge source ( option A )

Explanation:

When the Charge is first, Furthest away and second  and closest to the source charge. <em>The spring like bonds can be said to have No charge of the length  of the bonds expected because the rod did not touch the charge source </em><em>when Furthest away the bond with charge will be less effective </em>

5 0
3 years ago
A 150 kg bike takes a roundabout with a radius of 53.0 m. The roundabout it’s only ¾ of a circle. the time taken was 0.35 minute
BigorU [14]

Answer:

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Explanation:dfbgdhzfgbfxgzbfxd

fadwgfrsdfkyugılhşojipdaftshrthsxxfbzxryfchtgghxfjnx hjnnvbm bn dfkunggvxbvbbfbfxxb

5 0
3 years ago
You hold glider AA of mass 0.125 kgkg and glider BB of mass 0.375 kgkg at rest on an air track with a compressed spring of negli
andrew11 [14]

Answer:

The magnitude of the velocity of glider B is 0.2m/s and the direction is the negative direction  

Explanation:

Inelastic Collision

Given data

mass of glider A m1= 0.125kg

initial velocity u1=0

final velocity v1= 0.600 m/s

mass of glider B m2= 0.375kg

initial velocity u2=0

final velocity v2=?

We know that the expression for the conservation of momentum is given as

m1u1+m2u2=m1v1+m2v2

since u1=u2=u=0m/s

u(m1+m2)=m1v1+m2v2

substituting we have

0(0.125+0.0375)=0.125*0.6+0.375*v2

0=0.075+0.375v2

0.375v2=-0.075

v2=-0.075/0.375

v2=-0.2m/s

 The magnitude of the velocity of glider B is 0.2m/s and the direction is the negative direction      

3 0
3 years ago
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