Answer:
375.2 kJ
Explanation:
- H₂(g) +F₂(g) → 2HF(g) +536kJ
The information the equation above provides lets us know that when 2 mol of hydrogen fluoride (HF) are produced, 536 kJ of energy (as heat) is produced.
We can then <u>state a rule of three</u>:
And <u>solve for X</u>:
- X = 1.4 mol * 536 kJ / 2 mol
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