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omeli [17]
3 years ago
10

The atoms and molecules in a gas are in constant motion. Temperature is a measure of this motion. How are these related? As temp

erature increases, the molecules and atoms move faster. As temperature decreases, the molecules and atoms move farther apart. As temperature increases, the atoms and molecules move closer together. As temperature decreases, the molecules and atoms move faster.
Chemistry
1 answer:
Sedaia [141]3 years ago
8 0

Here we have to choose the correct statement on the effect of temperature on the motion of the molecules and atoms of a gas.

As the temperature increases the molecules and atoms move faster.

As per the kinetic theory of gas molecules and atoms the kinetic energy (K.E.) of the atom or molecules is related to temperature by the equation

K.E. = \frac{3}{2}kT ( k = Boltzmann constant, T = temperature.

Thus as the temperature increases the K.E. increases thus the atom or molecules move faster.

With the decrease of temperature the movement of the atoms or molecules will be less and they will be near to each other.

The increment of temperature increase the K.E. thus the atoms or molecules move apart from each other.

With the decrease of temperature the movement of the atoms or molecules decreases.  

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3 years ago
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Explanation:
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Since no mention of those conditions was made, I'll assume that the reaction takes place at STP, Standard Temperature and Pressure.
STP conditions are defined as a pressure of
100 kPa
and a temperature of
0
∘
C
. Under these conditions for pressure and temperature, one mole of any ideal gas occupies
22.7 L
- this is known as the molar volume of a gas at STP.
So, in order to find the volume of oxygen gas at STP, you need to know how many moles of oxygen are produced by this reaction.
The balanced chemical equation for this decomposition reaction looks like this
2
KClO
3(s]
heat
×
−−−→
2
KCl
(s]
+
3
O
2(g]
↑
⏐
⏐
Notice that you have a
2
:
3
mole ratio between potassium chlorate and oxygen gas.
This tells you that the reaction will always produce
3
2
times more moles of oxygen gas than the number of moles of potassium chlorate that underwent decomposition.
Use potassium chlorate's molar mass to determine how many moles you have in that
231-g
sample
231
g
⋅
1 mole KClO
3
122.55
g
=
1.885 moles KClO
3
Use the aforementioned mole ratio to determine how many moles of oxygen would be produced from this many moles of potassium chlorate
1.885
moles KClO
3
⋅
3
moles O
2
2
moles KClO
3
=
2.8275 moles O
2
So, what volume would this many moles occupy at STP?
2.8275
moles
⋅
22.7 L
1
mol
=
64.2 L
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