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Mashutka [201]
3 years ago
6

compare the magnitude and range of the four basic forces—gravitational, electromagnetic, weak nuclear and strong nuclear

Physics
1 answer:
Andrews [41]3 years ago
6 0

Answer:

The four fundamental forces magnitude and range are in order of Strong Nuclear Force > electromagnetic force > weak nuclear force > gravitational force.

Explanation:

The 4 fundamental force are weak nuclear force, strong nuclear force, em force and the gravitational force are discussed below.

Strongest force is the strong nuclear force as compared to all of them. It is very useful for capturing the atoms nucleus together despite the large repulsion which is occur between the same charges due to protons in the nucleus.

Electromagnetic Force is the 2nd strongest fundamental force. Magnetism and electricity  was thought  to be of 2 separate forces.

Weak Nuclear Force involves the W and Z bosons exchange. It has a very short range of    

Gravitational Force is the weakest between all the fundamental forces. However, due to its long range it is the most dominant force. It follows the inverse square law like but it is always attractive in nature.

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Research has shown ____ often depends on one's current status, circumstances, and expectations.
larisa86 [58]

Answer:

A. subjective well-being

Explanation:

A subjective well being does indeed often on the status, expectations and circumstances according to the theory of emotion. Also, there are flashcards on quizlet about this subject so if you want to learn more go there!

6 0
3 years ago
A runner traveling with an initial velocity of 1.1 m/s accelerates at a constant rate of 0.8 m/s2fora time of 2.0 s.(a).What is
pychu [463]

Answer:

The final velocity of the runner at the end of the given time is 2.7 m/s.

Explanation:

Given;

initial velocity of the runner, u = 1.1 m/s

constant acceleration, a = 0.8 m/s²

time of motion, t = 2.0 s

The velocity of the runner at the end of the given time is calculate as;

v = u + at

where;

v is the final velocity of the runner at the end of the given time;

v = 1.1 + (0.8)(2)

v = 2.7 m/s

Therefore, the final velocity of the runner at the end of the given time is 2.7 m/s.

7 0
3 years ago
. Starting from a stop at a traffic signal, a car speeds up to 20 m/s in 5 seconds. Calculate the acceleration of the car.
Dimas [21]

Answer: 4m/s²

Explanation:

At stop signal car speed iz 0 ; V1=0m/s

After t=5s  , car has speed is V2=20m/s

using:

a=(V2-V1)/t

a=(20m/s-0m/s)/5s

a=20m/s/5s

a=4m/s²

4 0
3 years ago
After a big snowfall, you take your favorite rocket‑powered sled out to a wide field. The field is 223 m223 m across, and you kn
pogonyaev

Answer:

11.7 s

Explanation:

In this problem, the rocket is moving in a uniform accelerated motion. We have the following data:

d = 223 m, the distance that the sled has to cover

a=3.25 m/s^2, the acceleration of the rocket

We can use therefore the following SUVAT equation:

d=ut+\frac{1}{2}at^2

where

d is the distance

u = 0 is the initial velocity of the sled (it starts from rest)

t is the time

a is the acceleration

Re-arranging the equation and substituting the numbers, we find the time it takes for the rocket to cross the field:

d=\frac{1}{2}at^2\\t=\sqrt{\frac{2d}{a}}=\sqrt{\frac{2(223)}{3.25}}=11.7 s

6 0
3 years ago
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4 years ago
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