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2 years ago

The higher the pressure on a liquid, the higher its boiling point temperature. true false

2 answers:

6 0

True.

At the surface of the earth for example, the atmospheric pressure is 1 atmosphere, and water boils at 100°C, but at lower atmospheric pressure say at hills or mountains water boils at a lesser temperature than 100°C.

Hence the higher the pressure on a liquid, the higher the temperature.

Alika [10]2 years ago

3 0

True, p1/t1=p2/t2. Pressure is related to temperature at which it boils so pressure does affect the boiling point.

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A force is a vector quantity. What does that mean?

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Answer: Acceleration due to gravity

Explanation: Force, F = mg, is a vector quantity because the acceleration due to gravity, g, is a vector quantity. Explanation: F = mg Where m is the mass (in kilograms) of the object in question and g is the acceleration due to gravity. Mass is a scalar quantity; mass has no dependence on direction whatsoever.

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1 year ago

The magnitude of the Poynting vector of a planar electromagnetic wave has an average value of 0.724 W/m2. What is the maximum va

Hitman42 [59]

Answer:

7.78x10^-8T

Explanation:

The Pointing Vector S is

S = (1/μ0) E × B

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S = (1/μ0) E B

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<S> = [1/(2 μ0)] E0 B0

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Also at any instant,

E = c B

where E and B are magnitudes, so it must also be true at the instant of peak values

E0 = c B0

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<S> = [1/(2 μ0)] (c B0) B0 = [c/(2 μ0)] (B0)²

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2 years ago

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2 years ago

Read 2 more answers

A 36.0 kg box initially at rest is pushed 5.00 m along a rough, horizontal floor with a constant applied horizontal force of 130

konstantin123 [22]

Answer:

(a) W = 650J

(b) Wf = 529.2J

(d) W = 0J

(e) ΔK = 120.8J

(f) v2 = 2.58 m/s

Explanation:

(a) In order to find the work done by the applied force you use the following formula:

$W=Fd$ (1)

F: applied force = 130N

d: distance = 5.0m

$W=(130N)(5.0m)=650J$

The work done by the applied force is 650J

(b) The increase in the internal energy of the box-floor system is given by the work done of the friction force, which is calculated as follow:

$W_f=F_fd=\mu Mgd$ (2)

μ: coefficient of friction = 0.300

M: mass of the box = 36.0kg

g: gravitational constant = 9.8 m/s^2

$W_f=(0.300)(36.0kg)(9.8m/s^2)(5.0m)=529.2J$

The increase in the internal energy is 529.2J

(c) The normal force does not make work on the box because the normal force is perpendicular to the motion of the box.

$W = 0J$

(d) The same for the work done by the normal force. The work done by the gravitational force is zero because the motion of the box is perpendicular o the direction of the gravitational force.

(e) The change in the kinetic energy is given by the net work on the box. You use the following formula:

$\Delta K=W_T$ (3)