Question

In the middle of town, State and Elm streets meet at an angle of 40º. A triangular pocket park between the streets stretches 100 yards along State Street and 53.2 yards along Elm Street. The area of the pocket park to the nearest tenth of a square yard is ____ square yards.

Answer 1

The area of the pocket park will be given by:
Area=1/2sin θ (ab)
θ=40°
a=100 yds
b=53.2 yds

thus
Area=1/2×sin 40×(100×53.2)
Area=1,709.82 sq. yds