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nlexa [21]
3 years ago
6

In a human nose, the total area of the region that detects our odors is about ¾ in^2. Compare that to the sensory organ of a hun

ting dog, whose nose has an active area of about 65 cm^2.
Chemistry
1 answer:
viva [34]3 years ago
6 0

Let it be x

\\ \sf\longmapsto \dfrac{3}{4}x=65

\\ \sf\longmapsto x=65\times \dfrac{4}{3}

\\ \sf\longmapsto x=\dfrac{260}{3}

\\ \sf\longmapsto x\approx82

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The density of helium is 0.17 g/L. What Is the mass of helium in a 5.4 L helium balloon? (2 sig figs) *
ioda

Answer:

The correct answer is 0.92 g

Explanation:

The density is defined as the mass per unit of volume:

Density= mass/volume

From the data provided:

volume= 5.4 L

density= 0.17 g/L

Thus, to calculate the mass of helium:

mass= density x volume = 0.17 g/L x 5.4 L= 0.918 g ≅ 0.92 g

6 0
3 years ago
What is the resistance of a 150 W lightbulb connected to a 24 V voltage source?
Luda [366]

Answer:

3.84 Ω

Explanation:

From the question given above, the following data were obtained:

Electrical power (P) = 150 W

Voltage (V) = 24 V

Resistance (R) =?

P = IV

Recall:

V = IR

Divide both side by R

I = V/R

P = V/R × V

P = V² / R

Where:

P => Electrical power

V => Voltage

I => Current

R => Resistance

With the above formula (i.e P = V²/R), we can calculate resistance as illustrated below:

Electrical power (P) = 150 W

Voltage (V) = 24 V

Resistance (R) =?

P = V²/R

150 = 24² / R

150 = 576 / R

Cross multiply

150 × R = 576

Divide both side by 150

R = 576 / 150

R = 3.84 Ω

Thus, the resistance is 3.84 Ω

4 0
2 years ago
In the evolution of extremely large stars, they begin as supergiants or supernovas, if the star nucleus is large enough it will
fenix001 [56]
Black hole, or a singularity contained within an event horizon through which no light can escape.
6 0
2 years ago
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andriy [413]

Answer:

ionic

Explanation:

4 0
2 years ago
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How many moles are in 7.2x10^15 atoms of Pb?​
fiasKO [112]
<h3>Answer:</h3>

1.2 × 10⁻⁸ mol Pb

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[Given] 7.2 × 10¹⁵ atoms Pb

<u>Step 2: Identify Conversions</u>

Avogadro's Number

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                     \displaystyle 7.2 \cdot 10^{15} \ atoms \ Pb(\frac{1 \ mol \ Pb}{6.022 \cdot 10^{23} \ atoms \ Pb})
  2. [DA] Multiply/Divide [Cancel out units]:                                                            \displaystyle 1.19562 \cdot 10^{-8} \ mol \ Pb

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs.</em>

1.19562 × 10⁻⁸ mol Pb ≈ 1.2 × 10⁻⁸ mol Pb

6 0
2 years ago
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