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3 years ago

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In a human nose, the total area of the region that detects our odors is about ¾ in^2. Compare that to the sensory organ of a hun

ting dog, whose nose has an active area of about 65 cm^2.

1 answer:

viva [34]3 years ago

6 0

Let it be x

$\\ \sf\longmapsto \dfrac{3}{4}x=65$

$\\ \sf\longmapsto x=65\times \dfrac{4}{3}$

$\\ \sf\longmapsto x=\dfrac{260}{3}$

$\\ \sf\longmapsto x\approx82$

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A solution of 0.207 M aspartic acid, the charge neutral form of the amino acid, is titrated with 0.0690 M NaOH . The pKa values

Softa [21]

Answer:

pH = 6,951

Explanation:

The neutral form of aspartic acid is in its isolectric point. For aspartic acid the isoelectric point is the average of pka1 and pka2, thus:

$pH =\frac{1}{2} (3,900+1,990)$ = 2,945

The addition of stoichiometric amounts of NaOH at the first equivalence point will increase the pH at average of pka2 and pka3 thus:

$pH = \frac{1}{2} (3,900+10,002)$ = 6,951

Thus, <em>pH at the first equivalence point is 6,951</em>

I hope it helps!

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3 years ago

For the following reaction, identify the element that was oxidized, the element that was reduced, and the reducing agent. Give a

Galina-37 [17]

The element oxidized is the element in which the charge becomes more positive after the reaction, hence the reducing agent. The element that is reduced is the element or compound in which the charge becomes more negative after the reaction. Sn becomes +4 from +2. Hence Sn is the reduced element while Pb becomes +2 from +4 hence Pb is the element oxidized and PbCl4 is the reducing agent.

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3 years ago

A solution of known concentration is called

oee [108]

Answer:

It is called standard solution.

Explanation:

I hope this helps! Have a nice dayy! :)

3 0

3 years ago

What are the SI units for specific heat capacity

KATRIN_1 [288]

The SI unit for specific heat capacity is the joule per kilogram Kelvin, J?kg-1?K-1 or J/(kg?K), which is the amount of energy required to raise the temperature of one kilogram of the substance by one Kelvin

7 0

3 years ago

Read 2 more answers

Using the mmoles of (35)-2,2,-dibromo-3,4-dimethylpentane calculated earlier and the molecular weight of the product (962 g/mol)

Sedbober [7]

Answer:

The yield of the product in gram is $\mathsf{{w_P}=0.26 \ gram}$

Explanation:

Given that:

the molecular mass weight of the product = 96.2 g/mol

the molecular mass of the reagent (3S)-2,2,-dibromo-3,4-dimethylpentane is 257.997 g

given that the millimoles of the reagent = 2,7 millimoles = $2.7 \times 10^{-3} \ moles$

We know that:

Number of moles = mass/molar mass

Then:

$2.7 \times 10^{-3} = \dfrac{ mass}{257.997}$

$mass = 2.7 \times 10^{-3} \times 257.997$

mass = 0.697

Theoretical yield = (number of moles of the product/ number of moles of reactant) × 100

i.e

Theoretical yield = $\dfrac{n_P}{n_R}\times 100\%$

where;

$n_P = \dfrac{w_P}{m_P}$ and $n_R = \dfrac{w_R}{m_R}$

Theoretical yield = $\dfrac{(\dfrac{w_P}{m_P})}{(\dfrac{w_R}{m_R})} \times 100\%$

Given that the theoretical yield = 100%

Then:

$100\% =\dfrac{(\dfrac{w_P}{m_P})}{(\dfrac{w_R}{m_R})} \times 100\%$

$\dfrac{w_P}{m_P}=\dfrac{w_R}{m_R}$

${w_P}=\dfrac{w_R \times m_P}{m_R}$

where,

$w_P$ = derived weight of the product

$m_P =$ the molecular mass of the derived product

$m_R =$ the molecular mass of the reagent

$w_R$ = weight in a gram of the reagent

${w_P}=\dfrac{w_R \times m_P}{m_R}$

${w_P}=\dfrac{0.697 \times 96.2}{257.997}$

$\mathsf{{w_P}=0.26 \ gram}$

8 0

3 years ago