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3 years ago

How many moles are in a balloon that is 50.2L, 755 mmHg and -22.0C?

Chemistry

1 answer:

Inessa05 [86]3 years ago

8 0

Answer:

n ≈ 2.42 moles

General Formulas and Concepts:

Chem

Ideal Gas Law: PV = nRT

P is pressure in mmHg
V is volume in liters
n is number of moles
R is a constant (62.4 L · mmHg/mol · k)
T is temperature in Kelvins

K = °C + 273

Explanation:

Step 1: Define

V = 50.2 L

P = 755 mmHg

T = -22.0°C = 251 K

Step 2: Find moles n

(755 mmHg)(50.2 L) = n(62.4 L · mmHg/mol · k)(251 K)

37901 mmHg · L = n(15662.4 L · mmHg/mol)

n = 2.41987 moles

Step 3: Check

We are given 3 sig figs. Follow sig fig rules.

2.41987 moles ≈ 2.42 moles

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The question is incomplete, the complete question is:

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Explanation:

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

The equation used is:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ ......(1)

We are given:

Given mass of $CaCO_3$ = 80 g

Molar mass of $CaCO_3$ = 100 g/mol

Putting values in equation 1, we get:

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$CaCO_3\rightarrow CaO+CO_2$

By stoichiometry of the reaction:

If 1 mole of $CaCO_3$ produces 1 mole of CaO

So, 0.8 moles of $CaCO_3$ will produce = $\frac{1}{1}\times 0.8=0.8mol$ of CaO

We know, molar mass of $CaO$ = 56 g/mol

Putting values in above equation, we get:

$\text{Mass of CaO}=(0.8mol\times 56g/mol)=44.8g$

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$\% \text{yield}=\frac{\text{Actual value}}{\text{Theoretical value}}\times 100$ ......(2)

Given values:

Actual value of the product = 39 g

Theoretical value of the product = 44.8 g

Plugging values in equation 2:

$\% \text{yield}=\frac{39 g}{44.8g}\times 100\\\\\% \text{yield}=87.05\%$

Hence, the % yield of the product is 87.05 %

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