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2 years ago

How many moles are in a balloon that is 50.2L, 755 mmHg and -22.0C?

Chemistry

1 answer:

Inessa05 [86]2 years ago

8 0

Answer:

n ≈ 2.42 moles

General Formulas and Concepts:

Ideal Gas Law: PV = nRT

P is pressure in mmHg
V is volume in liters
n is number of moles
R is a constant (62.4 L · mmHg/mol · k)
T is temperature in Kelvins

K = °C + 273

Explanation:

<u>Step 1: Define</u>

V = 50.2 L

P = 755 mmHg

T = -22.0°C = 251 K

<u>Step 2: Find moles </u><em><u>n</u></em>

(755 mmHg)(50.2 L) = n(62.4 L · mmHg/mol · k)(251 K)

37901 mmHg · L = n(15662.4 L · mmHg/mol)

n = 2.41987 moles

<u>Step 3: Check</u>

<em>We are given 3 sig figs. Follow sig fig rules.</em>

2.41987 moles ≈ 2.42 moles

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What geometry does VSEPR predict for the central atom in NCl3

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Answer:

Tetrahedral electron geometry and trigonal pyramidal molecular geometry.

Explanation:

The Lewis structure is shown in Figure 1.

The central N atom has three bonding pairs and one lone pair, for <em>four electron groups</em>.

VSEPR theory predicts a tetrahedral electron geometry with bond angles of 109.5°.

We do not count the lone pair in determining the molecular shape.

The molecular geometry is trigonal pyramidal (see Figure 2).

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3 years ago

A florist prepares a solution of nitrogen-phosphorus fertilizer by dissolving 5.66 g of NH₄NO₃ and 4.42 g of (NH₄)₃ PO₄ in enoug

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In finding the molarity of a solution, we use the following formula:

$M=moles soluteL solution$

What is Molarity?

The number of moles of the solute is calculated by dividing the mass of the solute by its molar mass.

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The molar mass of NH4NO3 and (NH4)3PO4 are 80.043 g/mol and 149.0867 g/mol, respectively.

$molesNH+4inNH4NO3=5.66 g80.043 g/mol×1molNH+41molNH4NO3=0.0707 mol$

$molesNH+4in(NH4)3PO4=4.42 g149.0867 g/mol×3molNH+41mol(NH4)3PO4=0.0889 mol$

$total molesNH+4=0.0707 mol+0.0889 mol=0.1596 mol$

$molesPO3−4in(NH4)3PO4=4.42 g149.0867 g/mol×1molPO3−41mol(NH4)3PO4=0.0296 mol$

$[NH+4]=0.1596 mol20.0 L=7.98×10−3 M NH+4$

$[PO3−4]=0.0296 mol20.0 L=1.48×10−3 M PO3−4$

Therefore, $[PO3−4]\\$ has a molarity of $1.48×10−3 M PO3−$

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1 year ago

A student explained to the class that helium has 8 valence electrons because it is in group 18. Is the student correct?

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<span>The student is incorrect because helium has 2 valence electrons and it's in group 18 because the first energy level is full. Although helium is placed in Group 18 which generally has 8 valence electrons, it does not have 8 valence electrons as the student suggested. It was grouped together with the noble gases because it exhibits similar properties with them. </span>

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3 years ago

A fish company delivers 22 kg of salmon, 5.5 kg of crab and 3.48 kg of oysters to your seafood restaurant. What is the mass, in

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Answer:

Mass of sea food = 30.98 Kg

Mass of sea food in pound = 68.31 lbs

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Salmon, crab and oysters all are sea food.

Mass of sea food = Mass of salmon + Mass of crab + mass of oyster

Mass of salmon = 22 kg

Mass of crab = 5.5 kg

Mass of oysters = 3.48 kg

Mass of sea food = Mass of salmon + Mass of crab + mass of oyster

= 22 + 5.5 + 3.48

= 30.98 Kg

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Therefore, 30.98 kg = 30.98 × 2.205

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2 years ago

The concentration of an HCl acid solution is initially 6mol/L. What would the concentration of a new solution be if 200 mL of th

pochemuha

Taking into account the definition of dilution, the concentration of the new solution is 1 mol/L.

<h3>Dilution</h3>

When it is desired to prepare a less concentrated solution from a more concentrated one, it is called dilution.

Dilution is the process of reducing the concentration of solute in solution, which is accomplished by simply adding more solvent to the solution at the same amount of solute.

In a dilution the amount of solute does not change, but as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.

A dilution is mathematically expressed as:

Ci×Vi = Cf×Vf

where

Ci: initial concentration
Vi: initial volume
Cf: final concentration
Vf: final volume

<h3>Final volume</h3>

In this case, you know:

Ci= 6 mol/L
Vi= 200 mL
Cf= ?
Vf= 1 L (1000 mL) water + 200 mL of HCL= 1200 mL

Replacing in the definition of dilution:

6 mol/L× 200 mL= Cf× 1200 mL

Solving:

(6 mol/L× 200 mL)÷ 1200 mL= Cf

In summary, the concentration of the new solution is 1 mol/L.

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1 year ago