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2 years ago

Keisha bought 1.2 pounds of Swiss cheese that was selling for $5.95 per pound.

Mathematics

2 answers:

puteri [66]2 years ago

8 0

Answer:

multiply

Step-by-step explanation:

pounds times $ per pound gives an answer in $$

Logic tells you if she buys more than a pound she will pay more total than the one pound price, so 1.2 x 5.95 = $7.14

In dollar problems, some teachers will mark points off if you don't round to the nearest cent because we don't use anything smaller than a penny.

Anna11 [10]2 years ago

5 0

Answer:

Keisha paid $7.0805

Step-by-step explanation:

First of all, you already know that 1 pound equals $5.95. Secondly, you have to solve 5.95 divided by 10, which is 0.595. However, the question is asking for 0.2 pounds! Therefore, 0.595 * 2 = 1.19.

But we're not done yet! We still have to find the amount of money in all. 5.95 * 1.19 = 7.0805 The sum of money in all is $7.0805

Hope this helps!

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What is least to greatest 2/8 2/1 3/4 5/6 7/6

yKpoI14uk [10]

Answer:

2/8, 3/4, 5/6, 7/6, 2/1

Step-by-step explanation:

To convert the fractions into ascending order (least to greatest):

1. Determine the LCM (Least common multiple) of the denominators.

2. Then, using the LCM, multiply such number to the denominators such that the product is equivalent to the LCM of the denominators.

Note: The number we multiply to the denominator must also be multiplied to the numerator.

3. Finally, create the set, in ascending order.

<h3>Determine the LCM of the denominators:</h3>

Given fraction set;

$\dfrac{2}{8} ; \ \dfrac{2}{1}; \ \dfrac{3}{4}; \ \dfrac{5}{6};\ \dfrac{7}{6}$

Therefore, the denominators of the fraction set are;

$\implies \text{Denominators: 8, 1, 4, 6, 6}$

Determining the LCM using Division method;

$\ \ \underline{................}\\2\underline{| 8, 1, 4, 6, 6}\\ 2\underline{|4, 1, 2, 3, 3} \\ 2\underline{|2,1,1,3,3} \\3 \underline{|1, 1,1,1,1}$

LCM of denominators: 2 × 2 × 2 × 3 = 24

<h3>Multiplying the denominators:</h3>

LCM of denominators: 24

<u>Multiply such number such that the denominators are equivalent to 24.</u>

$\implies \dfrac{2}{8} ; \ \dfrac{2}{1}; \ \dfrac{3}{4}; \ \dfrac{5}{6};\ \dfrac{7}{6}$

$\implies \dfrac{2 \times 3}{8 \times 3} ; \ \dfrac{2 \times 24}{1 \times 24} ; \ \dfrac{3 \times 6}{4 \times 6} ; \ \dfrac{5 \times 4}{6 \times 4} ; \ \dfrac{7 \times 4}{6 \times 4}$

$\implies \dfrac{6}{24} ; \ \dfrac{48}{24} ; \ \dfrac{18}{24} ; \ \dfrac{20}{24}; \ \dfrac{28}{24}$

<h3>Creating the set, in ascending order;</h3>

<u>Simply compare the fractions and put them in "smallest to biggest" order.</u>

$\implies \dfrac{6}{24} ; \ \dfrac{48}{24} ; \ \dfrac{18}{24} ; \ \dfrac{20}{24}; \ \dfrac{28}{24}$

$\implies \dfrac{6}{24} < \dfrac{18}{24} < \dfrac{20}{24} < \dfrac{28}{24} < \dfrac{48}{24}$

$\implies \dfrac{6}{24} \ \ \huge{\text{(}\dfrac{2}{8} } \text{)}; \ \dfrac{18}{24} \ \huge{\text{(}\dfrac{3}{4}\huge{\text{)} ; \ \dfrac{20}{24} \ \huge{\text{(}\dfrac{5}{6} \huge{\text{)} ; \ \dfrac{28}{24} \ \huge{\text{(} \dfrac{7}{6} \huge{\text{)}; \ \dfrac{48}{24} \ \huge{\text{(} \dfrac{2}{1} \huge{\text{)}$