All categories

3 years ago

Balance environment is useful for both plants and animals for their survival Why

Chemistry

2 answers:

professor190 [17]3 years ago

6 0

Answer:

In summary, the ecological balance brings the existence of the world. Earth's inhabitants such as human beings, plants, animals and other micro living organisms continue to survive. These species get the conducive environment to multiply and thrive. The world gets to produce sufficient food for all species.

may this help u

love history [14]3 years ago

5 0

Explanation:

balance between plants & animals is essential because plants are autotrophs , they can make their own food but animals are heterotrophs , they cannot prepare their own food so they have to depend on plants ( autotrophs) for their food.

moreover, to prepare their food plants need C02 , WHICH IS RELEASED IN THE ENVIRONMENT BY ANIMALS ( BY RESPIRATION) & IN TURN THEY RELEASE Oxygen which is essential for the life of animals & also to maintain balance in nature , the number of plants should be equal to the number of animals.

You might be interested in

Write the empirical formula of at least four binary ionic compounds that could be formed from the following ions: Zn2+, Ni4+, F-

hram777 [196]

Ionic compounds are formed between oppositely charged ions.

A binary ionic compound is composed of ions of two different elements - one of which is a positive ion(metal), and the other is negative ion (nonmetal).

To write the empirical formula of binary ionic compound we must remember that one ion should be positive and other ion should be negative, then only the correct formula should be written. To write the empirical formula the charges of opposite ions should be criss-crossed.

First empirical formula of binary ionic compound is written between $Zn^{2+} (Positive ion)and F^{-} (Negative ion)$

First Formula would be $ZnF_{2}$

Second empirical formula is between $Zn^{2+}(Positive ion) and O^{2-}(Negative ion)$

Second Formula would be $Zn_{2}O_{2}$

Note : When the subscript are same they get cancel out, so $Zn_{2}O_{2}$ would be written as $ZnO$

Third empirical formula is between $Ni^{4+}(Positive ion) and F^{-}(Negative ion)$

Third Formula would be : $NiF_{4}$

Forth empirical formula is between $Ni^{4+}(Positive ion)and O^{2-}(negative ion)$

Forth Formula would be : $Ni_{2}O_{4}$ or $NiO_{2}$

Note- The subscript will be simplified and the formula will be written as $NiO_{2}$ .

The empirical formula of four binary ionic compounds are : $ZnF_{2}, ZnO, NiF_{4},NiO_{2}$

8 0

3 years ago

Read 2 more answers

What is the difference between a theory and a law?

kondaur [170]

Answer:

theory is diffrent from law

Explanation:

a Theory can never be proven to be true nd a law can usually be expressed

3 0

3 years ago

What are some insulators and conductors of electricity? Name 2 of each

hammer [34]

Answer:

insulator:wood,rubber

conductor:aluminium,copper

4 0

3 years ago

Are the bonds in each of the following substances ionic, nonpolar covalent, or polar covalent? Arrange the substances with polar

KengaRu [80]

Covalent bonds can be classified as nonpolar and polar covalent given the electronegativity difference between two atoms (ΔEN).

Nonpolar covalent bond electrons are shared equally between two atoms, polar covalent bond electrons are shared unequally, atoms have partial charges, ionic bond electrons are completely transferred to one atom, full charges present. Therefore, the greater the electronegativity difference, the greater the bond polarity. Let's determine the types of bonds present in the compounds and arrange the ones with polar covalent in order of increasing ΔEN. Sulfur and oxygen are both nonmetals so the substance is covalent. Sulfur has EN = 2.5 and oxygen has EN = 3.5. Since there is an electronegativity difference, the S−O bonds in the substance can be classified as polar covalent bonds.

Learn more about polar covalent bond here:

brainly.com/question/25150590

#SPJ4

3 0

2 years ago

A parachute on a racing dragster opens and changes the speed of the car from 85 m/s to 45 m/s in a period of 4.5 seconds. What i

LiRa [457]

Answer:

- 8.89 $m/s^{2}$