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adelina 88 [10]
3 years ago
7

Can somebody help me with this question please

Chemistry
1 answer:
Tasya [4]3 years ago
7 0

Answer:

concave lens

Explanation:

it's concave lens because it diverges the ray/beam of light.

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Which could be the catalyst in a chemical reaction?
AlekseyPX

Answer:  C. enzyme

Explanation:

A catalyst is a substance which increases the rate of a reaction by taking the reaction through a different path which involves lower activation energy and thus more molecules can cross the energy barrier and convert to products.

The catalyst itself does not take part in the chemical reaction and is regenerated as such at the end.

Enzymes are proteins that reduce the activation energy of biological reaction. Enzymes increase the speed of a reaction and help it to run faster. Thus they are also called as bio catalysts.

Activated complex is the transition state which is very unstable and is formed during the course when reactants are converted to products.

4 0
3 years ago
Who wants to talk till 1am? hmu:)
Ulleksa [173]

Answer:

Explanation:

lol hi

3 0
3 years ago
A 0.2500 g sample of a compound known to contain carbon, hydrogen and oxygen undergoes complete combustion to produce 0.3664 gra
irga5000 [103]

Answer:

C₂H₅O₂

Explanation:

From the question given above, the following data were obtained:

Mass of compound = 0.25 g

Mass of CO₂ = 0.3664 g

Mass of H₂O = 0.15 g

Empirical formula =?

Next, we shall determine the mass of carbon, hydrogen and oxygen present in the compound. This can be obtained as follow:

For Carbon (C):

Mass of CO₂ = 0.3664 g

Molar mass of CO₂ = 12 + (2×16) = 44 g/mol

Mass of C = 12/44 × 0.3664

Mass of C = 0.1

For Hydrogen (H):

Mass of H₂O = 0.15 g

Molar mass of H₂O = (2×1) + 16 = 18 g/mol

Mass of H = 2/18 × 0.15

Mass of H = 0.02 g

For Oxygen (O):

Mass of C = 0.1 g

Mass of H = 0.02 g

Mass of compound = 0.25 g

Mass of O =?

Mass of O = (Mass of compound) – (Mass of C + Mass of H)

Mass of O = 0.25 – (0.1 + 0.02)

Mass of O = 0.25 –0.12

Mass of O = 0.13 g

Finally, we shall determine the empirical formula for the compound. This can be obtained as follow:

C = 0.1

H = 0.02

O = 0.13

Divide by their molar mass

C = 0.1 / 12 = 0.0083

H = 0.02 / 1 = 0.02

O = 0.13 / 16 = 0.0081

Divide by the smallest

C = 0.0083 / 0.0081 = 1

H = 0.02 / 0.0081 = 2.47

O = 0.008 / 0.008 = 1

Multiply by 2 to express in whole number

C = 1 × 2 = 2

H = 2.47 × 2 = 5

O = 1 × 2 = 2

Thus, the empirical formula for the compound is C₂H₅O₂

5 0
3 years ago
What is the reason that some elements are formed inside stars and nowhere else
elena-14-01-66 [18.8K]

I think it would be answer B or D  . I gave you two answer because I dont want to be wrong with one

6 0
3 years ago
Read 2 more answers
6. Para dos átomos que llamaremos x e y, justifica (en al menos dos
lesantik [10]

La primera instrucción es verdadera, la segunda es falsa porque dos elementos no pueden tener el mismo número de masa (excepto azufre y argón) Estrictamente hablando, No. Puede tener 2 (o más) elementos con el mismo 'número de masa atómica', lo que significa que el número total de nucleones (neutrones de protones) es el mismo. En el ejemplo dado en una respuesta anterior, el azufre tiene un isótopo con el número de masa atómica 36 (16p 20n) y Argón también tiene un 36 (18p 18n). La tercera declaración es verdadera, si tiene un número diferente de neutrones, entonces es un isótopo. La cuarta declaración es falso. Espero que esto te ayude.

5 0
3 years ago
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