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sergiy2304 [10]
3 years ago
8

Consider the unbalanced equation for the oxidation of aluminum.

Chemistry
2 answers:
SashulF [63]3 years ago
8 0
In order to balance an equation, we apply the principle of conservation of mass, which states that mass can neither be created nor destroyed. Therefore, the mass of an element before and after a reaction remains constant. Here, the balanced equation becomes:
4Al + 3O₂ → 2Al₂O₃

The coefficients are 4, 3 and 2.
Pani-rosa [81]3 years ago
8 0

Answer:

c

Explanation:

edg 2020

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Given 8.25 g of butanoic acid and excess ethanol, how many grams of ethyl butyrate would be synthesized, assuming a complete 100
mash [69]

Answer:

              10.87 g of Ethyl Butyrate

Solution:

The Balance Chemical Equation is as follow,

   H₃C-CH₂-CH₂-COOH + H₃C-CH₂-OH  →  H₃C-CH₂-CH₂-COO-CH₂-CH₃ + H₂O

According to equation,

    88.11 g (1 mol) Butanoic Acid produces  =  116.16 g (1 mol) Ethyl Butyrate

So,

           8.25 g Butanoic Acid will produce  =  X g of Ethyl Butyrate

Solving for X,

                      X =  (8.25 g × 116.16 g) ÷ 88.11 g

                      X =  10.87 g of Ethyl Butyrate

8 0
3 years ago
Bună ziua, mă poate ajuta și pe mine cineva, spunândumi din ce substanțe este formată cărămida și care este formula
Ne4ueva [31]

Answer: De câte cărămizi am nevoie? Pentru un perete de cărămidă cu strat singular, înmulțiți lungimea peretelui cu înălțimea pentru a obține zona. Înmulțiți acea zonă cu 60 pentru a obține numărul de cărămizi de care ar trebui să aveți nevoie, apoi adăugați 10% pentru risipă. Acesta este răspunsul scurt și presupune dimensiuni „standard” de cărămidă și mortar.

5 0
3 years ago
Determine the molar solubility of pbso4 in pure water. ksp (pbso4) = 1.82 x 10-8.
Misha Larkins [42]
Use the ICE table approach as solution:

           PbSO₄   --> Pb²⁺ + SO₄²⁻
I             -                 0          0
C           -                +s         +s
E           -                  s          s

Ksp = [Pb²⁺][SO₄²⁻]
1.82×10⁻⁸ = s²
Solving for s,
s = <em>1.35×10⁻⁴ M</em>
5 0
4 years ago
Determine the final temperature of sample with a specific heat of 1.1 J/g°C and a mass of 385 g if it starts out at a temperatur
Assoli18 [71]

Answer:

T2 =21.52°C

Explanation:

Given data:

Specific heat capacity of sample = 1.1 J/g.°C

Mass of sample = 385 g

Initial temperature = 19.5°C

Heat absorbed = 885 J

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = Final temperature - initial temperature

885J = 385 g× 1.1 J/g.°C×(T2 - 19.5°C )

885 J = 423.5 J/°C× (T2 - 19.5°C )

885 J / 423.5 J/°C = (T2 - 19.5°C )

2.02°C = (T2 - 19.5°C )

T2 = 2.02°C + 19.5°C

T2 =21.52°C

8 0
3 years ago
Consider n2 (g) + 3h2 (g) →→ 2nh3 (g). what is the mass of nitrogen gas required to react with 0.129 g h2?
Flura [38]
The given chemical reaction given above is already balanced such that the number of atoms in the left hand side of the equation is equal to that of the right hand side. Using the dimensional analysis, proper conversion factors and the molar masses,

                    mass of nitrogen = (0.129 g H₂)(1 mol H₂/2 g H₂)(1 mol N₂/3 mol H₂)(28 g N₂/1 mol N₂)
                     mass of nitrogen = 0.602 g N₂

Therefore, 0.602 g of nitrogen will be required for he reaction. 
6 0
3 years ago
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