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2 years ago

Please answer only number 4

Mathematics

2 answers:

sdas [7]2 years ago

8 0

Answer:

for question 4, 1/3 is the probability since there are 6 sides and there are two numbers on a die less than 3, 2 and 1.

2 and 1 are 2 of the 6 numbers on the die.

so 2/6

but we have to simplify!

divide 2 by 2 and 6 by 2

1/3 done!

Step-by-step explanation:

docker41 [41]2 years ago

6 0

<h3>Answer: 1/3</h3>

Explanation:

The set of outcomes we want to happen is {1,2}. These items are less than 3. We have A = 2 outcomes here.

There are B = 6 total outcomes in the set {1,2,3,4,5,6} which are values on a standard cube.

The probability we want is A/B = 2/6 = 1/3

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kkurt [141]

Answer:

Step-by-step explanation:

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As per options,

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1 year ago

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Step-by-step explanation:

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2 years ago

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natali 33 [55]

Answer:

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Step-by-step explanation:

The parts are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

50 parts means that $N = 50$

4 defective means that $k = 4$

10 are chosen, which means that $n = 10$

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Probability that none is defective, so:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,50,10,4) = \frac{C_{4,0}*C_{46,10}}{C_{50,10}} = 0.3968$

0.3968 = 39.68% probability this shipment passes inspection.

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2 years ago

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Damm [24]

Answer:

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Step-by-step explanation:

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