Answer:
FeCl₃
Explanation:
4FeCl₃ + 3O₂ => 2Fe₂O₃+ 6Cl₂
Given => 7moles 9moles
A simple way to determine which reagent is the limiting reactant is to convert all given data to moles then divide by the respective coefficients of the balanced equation. The smaller value will be the limiting reactant.
4FeCl₃ + 3O₂ => 2Fe₂O₃+ 6Cl₂
Given => 7/4 = 1.75* 9/3 = 3
*Smaller value => FeCl₃ is limiting reactant.
NOTE: However, when working problems, one must use original mole values given.
Answer:
Opaque → a.no light travels through the material; all light is reflected or absorbed
Translucent → b.some light travels through the material and the image cannot be seen clearly
Transparent → c.all light travels through the material and the image can be seen clearly
Explanation:
Hope this helps :)
The correct answer is Oxyanion Nitrite. Oxyanion is referred to as an ion which contains one or more oxygen atoms that are bonded to another chemical element. It has a generic formula of <span>A. </span>x<span>O </span>z− <span>y, wherein A, stands for a chemical element, while O, stands for an Oxygen atom</span>
This is most found commonly in cereal grains. Phytic acid is discovered in
the year 1903, a soaked cyclic acid, is the main storage form of phosphorus in numerous
plant tissues, particularly in bran and seeds. It can be found in cereals and
grain fibers.
<h3>
Answer:</h3>
3.3 × 10²³ molecules Cu(NO₃)₂
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
0.55 mol Cu(NO₃)₂
<u>Step 2: Identify Conversions</u>
Avogadro's Number
<u>Step 3: Convert</u>
- [DA] Set up:

- [DA] Multiply/Divide [Cancel out units]:

<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 2 sig figs.</em>
3.3121 × 10²³ molecules Cu(NO₃)₂ ≈ 3.3 × 10²³ molecules Cu(NO₃)₂