The statement that completes the query is: bytes / 1000 AS kilobytes
<h3>SQL (Structured Query Language)</h3>
This is the language that is used to retrieve, update, and store data in the database.
<h3>Columns</h3>
From the question, we have the following table columns
- track_id
- track_name (name of the music track)
- composer
- bytes (digital storage size of the music track
To retrieve data from the bytes column, we make use of:
SELECT bytes ......
From the question, we understand that this column should be divided by 1000, and the AS command should be used.
So, the query becomes
SELECT bytes / 1000 AS kilobytes .....
Hence, the statement that completes the query is: bytes / 1000 AS kilobytes
Read more about database at:
brainly.com/question/24223730
Answer:
You want to store, organize, and manipulate your photos. what type of software do you need?Adobe photoshop
sub heading:
what is photoshop?
Explanation:
1. you can dream it, you can make it with Adobe Photoshop.
2. Create beautiful images, graphics, paintings, and 3D artwork on your desktop or iPad
Reference link:
https://brainly.com
Hashtag:
#SPJ4
I'd go with yes, but are you doing something malicious or just being nosey?
Answer:
def leap_year(y):
if y % 4 == 0:
return 1
else:
return 0
def number_of_days(m,y):
if m == 2:
return 28 + leap_year(y)
elif m == 1 or m == 3 or m == 5 or m == 7 or m == 8 or m ==10 or m == 12:
return 31
elif m == 4 or m == 6 or m == 9 or m == 11:
return 30
def days(m,d):
if m == 1:
return 0 + d
if m == 2:
return 31 + d
if m == 3:
return 59 + d
if m == 4:
return 90 + d
if m == 5:
return 120 + d
if m == 6:
return 151 + d
if m == 7:
return 181 + d
if m == 8:
return 212 + d
if m == 9:
return 243 + d
if m == 10:
return 273 + d
if m == 11:
return 304 + d
if m == 12:
return 334 + d
def days_left(d,m,y):
if days(m,d) <= 60:
return 365 - days(m,d) + leap_year(y)
else:
return 365 - days(m,d)
print("Please enter a date")
day=int(input("Day: "))
month=int(input("Month: "))
year=int(input("Year: "))
choice=int(input("Menu:\n1) Calculate the number of days in the given month.\n2) Calculate the number of days left in the given year.\n"))
if choice == 1:
print(number_of_days(month, year))
if choice == 2:
print(days_left(day,month,year))
Explanation:
Hoped this helped
Answer:
29
Explanation:
for n=28:
--------------
Algorithm 1 performs f(n) = n2 + n/2 = 28*28 + 28/2 = 798
Algorithm 2 performs f(n) = 12*28 + 500 = 836
for n=29
--------------
Algorithm 1 performs f(n) = n2 + n/2 = 29*29 + 29/2 = 855.5
Algorithm 2 performs f(n) = 12*29 + 500 = 848
so, for n=29, algorithm 2 will be faster than algorithm 1
