Question

I don't know how to put this answer in.

Answer 1

Answer:

$i \times j = k \\ j \times k = i \: and \: k \times i = j \\ \\ j \times i= - k \\ k \times j = - i \\ i \times k = - j \\ \\ (i - k) \times (k - j) = \\ i \times k - (i \times j) - \\ (k \times k) + (k \times j) \\ note \\ \: i \times i = j \times j = k \times k = 0$