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bogdanovich [222]
3 years ago
13

Deposition refers to a change from the _______ phase to the solid phase.

Chemistry
1 answer:
Harman [31]3 years ago
6 0
Answer is: liquid

It’s gonna be liquid
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The shorter an elecrtomagnetic waves wavelength, the ___
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<h3>Answer:</h3>

The higher is its frequency.

<h3>Explanation:</h3>
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Kelly has some sand in a bucket, but she thinks that there may be some salt mixed in with her sand. How can she determine if the
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<span>Kelly has some sand in a bucket, but she thinks that there may be some salt mixed in with her sand. How can she determine if there is salt in the sand?</span><span>

 Answer: If she puts water in the bucket, the salt will dissolve.

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3 years ago
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What is the concentration, in m/v percent, of a solution prepared from 50 g NaCl and 2.5 L of solution?
Serjik [45]
When we convert the given mass in grams and volume in liters to m/v percent, we recall that m/v percent is expressed as grams/100 milliliters. In this case the expression becomes (50 grams/ 2500 L)*(0.1L/100ml), that is equal to 0.002 grams/ 100 mL. Hence the the concentration is equal to 0.2 m/v percent.
4 0
3 years ago
Name the following chemical compound.
olya-2409 [2.1K]
A. sulfur dioxide ...................................................
8 0
4 years ago
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How much energy is required to melt a 20.0lb bag of ice a 0°c? A pound (lb.) is equivalent to 0.4536. The Hfusion of ice is +6.0
erma4kov [3.2K]
To compute the energy, Q, needed to melt a certain amount of ice, n, in moles, we have

Q = n \Delta H_{f}

where the latent heat of fusion for ice is equal to 6.009 kJ/mol.

Now, since we have a 20.0 lb ice, we must first convert its mass to grams. Thus mass = (20.0)(1000)(0.4536) = 9072 g.

To find the number of moles present, we must recall that the molar mass of water (ice) is equal to <span>1.00794(2) + </span><span>15.9994 </span>≈ 18.01 g/mol. Hence, we have

ice_{moles} = (\frac{9072 g}{1})(\frac{1 mol}{18.01 g}) =503.72 moles

Now, to compute for the molar heat of fusion, Q,

Q = (503.72)(6.009) = 3026.9 kJ

Therefore, the amount of heat needed to melt the 20-lb bag of ice is equal to 3026.9 kJ.
 
Answer: 3026.9 kJ
6 0
3 years ago
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