7/8 and 9/16
7*2/8*2 = 14/16
14/16 and 9/16
Now since we have a common denominator, we can compare the numerators.
14/16 is greater, so 7/8 is greater than 9/16
Answer: 7/8 is bigger
Answer:
Vaush
Step-by-step explanation:
Answer:
The correct option is 4.
Step-by-step explanation:
The given expression is
Simplify the given expression.
![[\because x^mx^n=x^{m+n}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20x%5Emx%5En%3Dx%5E%7Bm%2Bn%7D%5D)
Therefore correct option is 4.
2/7 as a fraction rounds to 0.3
0.3 * 3 = 0.9
3 x 2/7 is less than 3
Is RS perpendicular to DF? Select Yes or No for each statement. R (6, −2), S (−1, 8), D (−1, 11), and F (11 ,4) R (1, 3), S (4,7
guajiro [1.7K]
I'll do the first one to get you started.
Find the slope of the line between R (6,-2) and S (-1,8) to get
m = (y2-y1)/(x2-x1)
m = (8-(-2))/(-1-6)
m = (8+2)/(-1-6)
m = 10/(-7)
m = -10/7
The slope of line RS is -10/7
Next, we find the slope of line DF
m = (y2 - y1)/(x2 - x1)
m = (4-11)/(11-(-1))
m = (4-11)/(11+1)
m = -7/12
From here, we multiply the two slope values
(slope of RS)*(slope of DF) = (-10/7)*(-7/12)
(slope of RS)*(slope of DF) = (-10*(-7))/(7*12)
(slope of RS)*(slope of DF) = 10/12
(slope of RS)*(slope of DF) = 5/6
Because the result is not -1, this means we do not have perpendicular lines here. Any pair of perpendicular lines always has their slopes multiply to -1. This is assuming neither line is vertical.
I'll let you do the two other ones. Let me know what you get so I can check your work.
