Look at this graph:

Andesitic rock is an igneous rock with a composition in between that of basaltic and granitic igneous rock.

Ne4ueva [31]

Answer:

Explanation:

intristing

8 0

3 years ago

What is the result of an uncontrolled chain reaction

vazorg [7]

A chain reaction is a nuclear reaction that occurs when sufficient unstable nuclei are present so that when one splits (decays), its products hit other unstable nuclei, causing them to decay and initiating a chain reaction.

If this reaction goes uncontrolled, a massive explosion occurs. Such a reaction is the type that went uncontrolled when nuclear bombs were dropped over Hiroshima and Nagasaki in World War II. A chain reaction is much like dominoes all in a row; when one goes down, they all go down in order. The only way to block the chain reaction is to pull out a domino or to block the fall so the "chain" is broken.

The amount of fissionable material needed to accomplish a spontaneous chain reaction is called the critical mass. The critical mass for U-235 is about 1 kg. This explosive fission process takes place quickly, and an incredible amount of energy is released when it occurs.

So it would be C.

4 0

4 years ago

Read 2 more answers

What is the density of air at 75 F and latm pressure? Express in lbm/ft3 and kg/m3

ser-zykov [4K]

Answer : The density of air in $lbm/ft^3$ and $kg/m^3$ is, $0.0743lbm/ft^3$ and $1.19kg/m^3$ respectively.

Explanation :

$PV=nRT\\\\PV=\frac{m}{M}RT\\\\P=\frac{m}{V}\frac{RT}{M}\\\\P=\rho \frac{RT}{M}\\\\\rho=\frac{PM}{RT}$

where,

P = pressure of air = 1 atm

V = volume of air

T = temperature of air = 297 K

The conversion used for the temperature from Fahrenheit to degree Celsius is:

$^oC=(^oF-32)\times \frac{5}{9}$

$^oC=(75-32)\times \frac{5}{9}=24^oC$

The conversion used for the temperature from degree Celsius to Kelvin is:

$K=273+^oC$

$K=273+24=297K$

n = number of moles

m = mass of air

M = average molar mass of air = 28.97 g/mole

$\rho$ = density of air = ?

R = gas constant = 0.0821 L.atm/mol.K

Now put all the given values in the above formula, we get:

$\rho=\frac{PM}{RT}$

$\rho=\frac{(1atm)\times (28.97g/mole)}{(0.0821L.atm/mol.K)\times (297K)}$

$\rho=1.19g/L$

Now we have to calculate density in $lbm/ft^3$ .

Conversion used :

$1g/L=0.0624lbm/ft^3$

So,

$1.19g/L=\frac{1.19g/L}{1g/L}\times 0.0624lbm/ft^3=0.0743lbm/ft^3$

The density of air in $lbm/ft^3$ is, $0.0743lbm/ft^3$

Now we have to calculate density in $kg/m^3$ .

Conversion used :

$1g/L=1kg/m^3$

So,

$1.19g/L=1.19kg/m^3$

The density of air in $kg/m^3$ is, $1.19kg/m^3$

8 0

3 years ago

Here is the information: A 1.2516 gram sample of a mixture of CaCO3 and Na2SO4 was analyzed by dissolving the sample and adding

tiny-mole [99]

Answer:

93,32 % (w/w)

Explanation:

The Ca²⁺ of CaCO₃ was completely precipitate to CaC₂O₄ that results in H₂C₂O₄. The titration of this one is:

3H₂C₂O₄ + 2H⁺ + MnO₄⁻ → Mn²⁺ + 4H₂O + 6CO₂

As you required 35,62mL of 0,1092M MnO₄⁻, the moles of H₂C₂O₄ are:

0,03562L× $\frac{0,1092M}{L}$ =

3,890x10⁻³mol of MnO₄⁻× $\frac{3molH_{2}C_{2}O_{4}}{1mol MnO_{4}^-}$ = 0,01167 mol of H₂C₂O₄

The number of moles of CaCO₃ are the same number of moles of H₂C₂O₄ because every Ca²⁺ was converted in CaC₂O₄ that was converted in H₂C₂O₄. That means: 0,01167 mol of CaCO₃

0,01167 mol of CaCO₃ are:

0,01167 mol of CaCO₃× $\frac{100,0869g}{1mol}$ = 1,168 g of CaCO₃

As the mass of the initial mixture is 1,2516 g, the percentage by weight of CaCO₃ is:

$\frac{1,168g}{1,2516g}$ ×100 = 93,32 % (w/w)

I hope it helps!

7 0

3 years ago

Multicellular plants and animals have warden super for specific functions what do eukaryotic cells have to perform specific func

Y_Kistochka [10]

Eukaryota Cells have to Preform: Organelles.

3 0

3 years ago