the force between the electron and the proton.
a) Use F = k * q1 * q2 / d²
where k = 8.99e9 N·m²/C²
and q1 = -1.602e-19 C (electron)
and q2 = 1.602e-19 C (proton)
and d = distance between point charges = 0.53e-10 m
The negative result indicates "attraction".
the radial acceleration of the electron.
b) Here, just use F = ma
where F was found above, and
m = mass of electron = 9.11e-31kg, if memory serves
a = radial acceleration
the speed of the electron.
c) Now use a = v² / r
where a was found above
and r was given
<span> the period of the circular motion.</span>
d) period T = 2π / ω = 2πr / v
where v was found above
and r was given
Answer:
1.33 × 10⁻³ m³
Explanation:
Step 1: Given data
Side of the cube (d): 11.0 cm
Step 2: Calculate the volume of the cube (V)
We will use the following expression.
V = d³
V = (11.0 cm)³
V = 1.33 × 10³ cm³
Step 3: Convert "V" to m³
We will use the conversion factor 1 m³ = 10⁶ cm³.
1.33 × 10³ cm³ × (1 m³ / 10⁶ cm³) = 1.33 × 10⁻³ m³
Answer:
68 grams
Explanation:
Reaction that produces ammonia when nitrogen and hydrogen reacts is given by :-
+ 3
→ 2N
Clearly ,
When one mole of nitrogen reacts , two moles of ammonia will be produced.
Now,
weight of 1 mole of the Nitrogen = 28.0 grams
In 56.0 grams of the nitrogen , two moles will be present.
Thus , 4 moles of ammonia will be produced .
Weight of one mole of nitrogen = 17 grams.
Thus a total of 17× 4 = 68 grams f nitrogen will be produced.
