Answer:
1.5 × 10³ g
Explanation:
Step 1: Given and required data
- Transferred heat (Q): 41,840 J
- Initial temperature: 22.0 °C
- Final temperature: 28.5 °C
- Specific heat capacity of water (c): 4.184 J/g.°C
Step 2: Calculate the temperature change
ΔT = 28.5°C - 22.0 °C = 6.5 °C
Step 3: Calculate the mass (m) of water
We will use the following expression.
Q = c × m × ΔT
m = Q / c × ΔT
m = 41,840 J / (4.184 J/g.°C) × 6.5 °C = 1.5 × 10³ g
A covalent bond (I’m assuming that’s what you mean)
If the EN difference is less than 1.7, it’s a covalent bond
Answer:
D. The coefficients tell the ratio of moles of reactants used in the reaction
Explanation:
The molar ratio is central to all stoichiometric calculations.
To get the mass of Compound B that reacts with compound A, you must
- Convert the mass of A to moles
- Use the molar ratio from the balanced equation to find the moles of B
- Convert moles of B to grams.
You must get over the "mole hill."