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GalinKa [24]
3 years ago
13

A concentration cell is constructed by using the same half-reaction for both the cathode and anode. What is the value of standar

d cell potential, for a concentration cell that combines a silver anode in contact with 0.10 M silver nitrate and a silver cathode in contact with 0.00003 M silver nitrate
Chemistry
1 answer:
Akimi4 [234]3 years ago
7 0

Solution :

A cell that is concentrated is constructed by the same half reaction for the anode as well as he cathode.

We know,

In a standard cell,

the reduction half cell reaction is :

$Ag^+(aq)+e^- \rightarrow Ag(s) E^0 = -0.80 \ V$

The oxidation half ell reaction :

$Ag(s) \rightarrow Ag^+(aq) + e^- \ E^0= +0.80 \ V$

Thus the complete reaction of the cell is :

$Ag^+(aq)+ Ag(s) \rightarrow Ag^+(aq)+Ag(s)$

$E^0 $ cell = $E_R - E_L = 0.00  \ \text{volts}$

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The density of benzene is 0.879g/mL. The volume (with 1 decimal) of 131.9g sample of benzene is how many mL?
timurjin [86]

Answer:

150.1 mL

Explanation:

Step 1: Given data

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  • Mass of the sample of benzene (m): 131.9 g
  • Volume of the sample of benzene (V): ?

Step 2: Calculate the volume of the sample of benzene

Density is an intrinsic property. It is equal to the quotient between the mass and the volume of the sample of benzene.

ρ = m/V

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3 years ago
An empty vial weighs 55.32 g. (a) If the vial weighs 185.56 g when filled with liquid mercury (d = 13.53 g/cm3). What i its volu
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Answer:

a) Volume of vial= 9.626cm3

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a) Mass of empty vial = 55.32 g

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Therefore,

mass\ of\ Hg = 185.56-55.32 = 130.24 g

Density of Hg = 13.53 g/cm3

Volume\ of\ vial = Volume\ of\ Hg = \frac{Mass}{Density} \\\\= \frac{130.24g}{13.53g/cm3} = 9.626 cm3

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