23. The pilot of a small private plane can look forward and see the control tower for a small airstrip.
1 answer:
Answer:
Altitude of the plane is 0.5 miles.
Step-by-step explanation:
From the figure attached,
An airplane A is at height h miles observes a small airstrip at D and a factory at F, 4.8 miles apart from D.
Angle of depressions for the airstrip is 13.1° and the factory is 4.1°.
We have to calculate the airplane's altitude h.
From ΔABF,
tan4.1 =
h = 0.07168(x + 4.8) -----(1)
From ΔABD,
tan13.1 =
h = 0.2327x -----(2)
From equation (1) and (2),
0.07168(x + 4.8) = 0.2327x
0.2327x - 0.07168x = 4.8×0.07168
0.161x = 0.344
x = miles
From equation (2),
h = 0.2327×2.137
h = 0.4972 miles
h ≈ 0.5 miles
Therefore, 0.5 miles is the altitude of the plane.
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Answer:
y + 4 = 4/3(x - 6).
Step-by-step explanation:
The point-slope formula is shown below. We just need to find the slope.
(-4 - (-8)) / (6 - 3) = (-4 + 8) / 3 = 4 / 3
m = 4/3, y1 = -4, and x1 = 6.
y - (-4) = 4/3(x - 6)
y + 4 = 4/3(x - 6).
Hope this helps!
