Lets calculate gear ration T2/T1
so the gear ratio will be 1.6 it simply means dat if u rotate large gears one full revolution it tends to turn another short wheel to 1.6 revs, so in ur qtion the large whell revs 100 den u must multiply wid 1.6*100= 160 revs
Answer:
As eq of line passing through 2 points is
y-y1 = (y2-y1)/(x2-x1) ][ x -x1)
where (X1,y1)( x2, y2) denotes points lying on line
substitute (X1 ,y1) by( -1,-2) and (X2,y2) by( 2,4)
y+2 = 6/3 )( x+1)
y+2= 2x +2
y = 2x is required equation
∆BOC is equilateral, since both OC and OB are radii of the circle with length 4 cm. Then the angle subtended by the minor arc BC has measure 60°. (Note that OA is also a radius.) AB is a diameter of the circle, so the arc AB subtends an angle measuring 180°. This means the minor arc AC measures 120°.
Since ∆BOC is equilateral, its area is √3/4 (4 cm)² = 4√3 cm². The area of the sector containing ∆BOC is 60/360 = 1/6 the total area of the circle, or π/6 (4 cm)² = 8π/3 cm². Then the area of the shaded segment adjacent to ∆BOC is (8π/3 - 4√3) cm².
∆AOC is isosceles, with vertex angle measuring 120°, so the other two angles measure (180° - 120°)/2 = 30°. Using trigonometry, we find
where 
is the length of the altitude originating from vertex O, and so
where 
is the length of the base AC. Hence the area of ∆AOC is 1/2 (2 cm) (4√3 cm) = 4√3 cm². The area of the sector containing ∆AOC is 120/360 = 1/3 of the total area of the circle, or π/3 (4 cm)² = 16π/3 cm². Then the area of the other shaded segment is (16π/3 - 4√3) cm².
So, the total area of the shaded region is
(8π/3 - 4√3) + (16π/3 - 4√3) = (8π - 8√3) cm²
Answer:
how would i know the answer
Step-by-step explanation:
Answer: You bought 7 books and you also bought 4 magazines
Explanation:
x = # of books purchased
y = # of magazines purchased
System of equations:
8x + 5y = 76
x + y = 11
Let’s use elimination in this case, but substitution can also work.
8x + 5y = 76
Multiply the (x + y = 11) by -8
We get:
8x + 5y = 76
-8x - 8y = -88
The xs cancel.
Add like terms.
-3y = -12
Divide by -3 on both sides
y = 4
Now plug in 4 into the (x + y = 11) equation to get x.
x + (4) = 11
Subtract 4 on both sides
x = 7
