Answer:
0.500 M
Explanation:
The balanced equation for the neutralization reaction is as follows
NaOH + HCl —> NaCl + H2O
Molar ratio of NaOH to HCl is 1:1
Number of moles of NaOH reacted is equal to the number of HCl moles
We can use the following equation
c1v1 = c2v2
Where c1 is concentration and v1 is volume of HCl
c2 is concentration and v2 is volume of NaOH
Substituting the values
1.00 M x 10.0 mL = c2 x 20.0 mL
c2 = 0.500 M
Concentration of NaOH is 0.500 M
Answer:
1. Used in many smoke detectors for homes and businesses to measure levels of toxic lead in dried paint sample to ensure uniform thickness in rolling processes like steel and paper production and to help determine where oil wells should be drilled.
2.Used to treat cancerous tumors to measure correct patient dosages of radioactive pharmaceutical to measure and control the liquid flow in oil pipelines to tell researchers whether oil wells are plugged by sand and to ensure the right fill level for packages of food, drugs, and other
products.
3.Used in medical diagnosis
4.Used to treat thyroid disorders. (Graves’s disease).
5.Used in molecular biology and genetics research.
6.Used in nuclear medicine for lung ventilation and blood flow studies.
7.Used in dental fixtures like crowns and dentures to provide a Uranium-234 natural color and brightness.
8.Used in electric blanket thermostats and to gauge the thickness of thin plastics, thin sheet metal, rubber, textile and paper.
Answer: 0.424 J/g°C
Explanation:
For this problem, we would have to manipulate the equaiton for heat, q=mCT. Specific heat is the C in the equation. Since we are looking for specific heat, we manipulate the equation so that it says C=.
*I didn't know how to type in delta so I just wrote the word delta, but pretend you see a Δ.
Now that we have our equation, we can plug in our values and solve.
*Please ignore the capital A in the equation. It pops up every time I type in the ° sign.
Given buffer:
potassium hydrogen tartrate/dipotassium tartrate (KHC4H4O6/K2C4H4O6 )
[KHC4H4O6] = 0.0451 M
[K2C4H4O6] = 0.028 M
Ka1 = 9.2 *10^-4
Ka2 = 4.31*10^-5
Based on Henderson-Hasselbalch equation;
pH = pKa + log [conjugate base]/[acid]
where pka = -logKa
In this case we will use the ka corresponding to the deprotonation of the second proton i.e. ka2
pH = -log Ka2 + log [K2C4H4O6]/[KHC4H4O6]
= -log (4.31*10^-5) + log [0.0451]/[0.028]
pH = 4.15
Answer:
= 97.44 Liters at S.T.P
Explanation:
The reaction between Iron (iii) oxide and Carbon monoxide is given by the equation;
Fe2O3(s)+ 3CO(g) → 3CO2(g) + 2Fe(s)
From the reaction when the reactants react, 2 moles of Fe and 3 moles of CO2 are produced.
Therefore; Mole ratio of Iron : Carbon dioxide is 2:3
Thus; Moles of Carbon dioxide = (2.9/2)×3
= 4.35 moles
But; 1 mole of CO2 at s.t.p occupies 22.4 liters
Therefore;
Mass of CO2 = 22.4 × 4.35 Moles
= 97.44 L