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sattari [20]
3 years ago
7

If a large marshmallow has a volume of 2.50 i n 3 and density of 0.242 g/c m 3 , how much would it weigh in grams? 1 i n 3 =16.3

9 c m 3 .
Chemistry
1 answer:
Illusion [34]3 years ago
4 0

Density of a substance is defined as the mass of the substance divided by the volume.

Density of the substance= 0.242 g cm⁻³  

volume of the substance= 2.50 in³  

As, 1 in³= 16.39 cm³  

So, 2.50 in³= 16.39× 2.50 cm³=40.97 cm³

As ,  

Density=\frac{mass}{volume}  

Mass=volume ×Density

Mass=40.97 × 0.242

Mass=9.916 g.

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3 0
3 years ago
1) The heat of combustion for the gases hydrogen, methane and ethane are −285.8, −890.4 and −1559.9 kJ/mol respectively at 298K.
Morgarella [4.7K]

Answer:

The enthalpy of the reaction is 64.9 kJ/mol.

Explanation:

H_2 + \frac{1}{2}O_2\rightarrow H_2O,\Delta H_1 =-285.8 kJ..[1]

CH_4 + 2O_2\rightarrow CO_2 + 2H_2O,\Delta H_2 =-890.4 kJ..[2]

C_2H_6 + \frac{7}{2}O_2\rightarrow 2CO_2 + 3H_2O,\Delta H_3= -1559.9 kJ..[3]

2CH_4(g)\rightarrow C_2H_6(g) + H_2(g),\Delta H_4=?..[4]

2 × [2] - [1]- [3] = [4]  (Using Hess's law)

\Delta H_4=2\times \Delta H_2 -\Delta H_1 -\Delta H_3

\Delta H_4=2\times (-890.4 kJ)-(-285.8 kJ) -(-1559.9 kJ)

\Delta H_4=64.9 kJ/mol

The enthalpy of the reaction is 64.9 kJ/mol.

3 0
3 years ago
How many atoms are in 4.5 x 1022 moles of CO2?
weeeeeb [17]

The number of atoms : N = 2.709 x 10⁴⁶

<h3>Further explanation</h3>

Given

4.5 x 10²² moles of CO₂

Required

The number of atoms

Solution

The mole is the number of particles(molecules, atoms, ions) contained in a substance  

1 mol = 6.02.10²³ particles

Can be formulated

N=n x No

N = number of particles

n = mol

No = Avogadro's = 6.02.10²³

Input the value :

N = 4.5 x 10²² x 6.02 x 10²³

N = 2.709 x 10⁴⁶

8 0
3 years ago
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iragen [17]

Answer:

Products are AgBr and KNO3

4 0
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If an automobile air bag has a volume of 11.5 l , what mass of nan3 (in
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8 0
3 years ago
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