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2 years ago

Name three skills that you think you need to graduate from college, community college, or

Chemistry

2 answers:

Alik [6]2 years ago

3 0

Answer:

understanding people, organize notes correctly, learn how to organize your time wisely.

Explanation:

kozerog [31]2 years ago

3 0

Answer:

mathematics,English, and social skills.

Explanation:

math, and english because u eill need them for most of your class. social skills for like when you need projects or when u need hell with stuff.

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Why does the moon appear to be so bright in the sky

Nana76 [90]

Because of the sun reflects onto the moon and makes it brighter.

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2 years ago

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An unknown gas effuses 1.66 times more rapidly than CO2. What is the molar mass of the unknown gas, given that the molar mass of

Y_Kistochka [10]

The molar mass is 16.0 grams

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3 years ago

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If potassium (K) has a density of 0.86 g/cm3, which element would have a similar density?

Nata [24]

Answer:

C: Sodium

Explanation:

Iron had a way higher density neon has way to know as well as carbon and the closest one is sodium

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3 years ago

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A gas with a volume of 4.0L at a pressure of 205 kPa is allowed to expand to a volume of 12000 mL. What is the pressure in atmos

Leni [432]

Answer: The pressure in atmospheres is 0.674 in the container if the temperature remains constant.

Explanation:

Boyle's Law: This law states that pressure is inversely proportional to the volume of the gas at constant temperature and number of moles.

$P\propto \frac{1}{V}$ (At constant temperature and number of moles)

$P_1V_1=P_2V_2$

where,

$P_1$ = initial pressure of gas = 205 kPa

$P_2$ = final pressure of gas = ?

$V_1$ = initial volume of gas = 4.0 L

$V_2$ = final volume of gas = 12000 ml = 12 L (1L=1000ml)

$205\times 4.0=P_2\times 12$

$P_2=68.3kPa=0.674atm$ (1kPa=0.0098atm)

Therefore, the pressure in atmospheres is 0.674 in the container if the temperature remains constant.

8 0

3 years ago

Substance P is carbon.

stepan [7]

Explanation:

substance Q could be oxygen (O2)

substance R could be carbon dioxide (CO2)

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3 years ago