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BigorU [14]
3 years ago
14

22. An investigation of the relationship between the independent and dependent variables

Physics
1 answer:
Alisiya [41]3 years ago
3 0

Answer:

c. experiments

Explanation:

.......

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Sveta_85 [38]
The answer is b. All you have to do is find the intercepts.
6 0
3 years ago
The specific heat of aluminum is 0.90 J/gC . How much heat is given off when 25 grams of aluminum is cooled from 55 C to 25 C?
xxMikexx [17]

Answer:

Q = 675 [J]

Explanation:

We can calculate the amount of heat transfer by means of the following expression that includes the mass and temperature change in a body as a function of the specific heat.

Q=m*C_{p}*(T_{initial}-T_{final})

where:

m = mass = 25 [gr]

Cp = specific heat = 0.9 [J/g*°C]

Tinitial = 55 [°C]

Tfinal = 25 [°C]

Q=25*0.9*(55-25)\\Q=675 [J]

4 0
3 years ago
Based on your answer,what idea comes in to your mind?​
valkas [14]

Answer:

Homework · Free food · Loosing and robbing pencil · Forgetting book at home · Waiting for a Play time · My first bit · Lunch sharing · Assembly lines- standing in last just ...

Explanation:

5 0
3 years ago
5. How does privatization contribute to productivity?
tangare [24]

Answer:

increased competition

Explanation:

3 0
2 years ago
Calculate the nuclear binding energy per nucleon for 136^Ba if its nuclear mass is 135.905 amu.
kompoz [17]

Answer:

1.312 x 10⁻¹² J/nucleon

Explanation:

mass of ¹³⁶Ba = 135.905 amu

¹³⁶Ba contain 56 proton and 80 neutron

mass of proton = 1.00728 amu

mass of neutron = 1.00867 amu

mass of ¹³⁶Ba = 56 x  1.00728 amu + 80 x 1.00867 amu

                      = 137.10128 amu

mass defect = 137.10128 - 135.905

                    = 1.19628 amu

mass defect = 1.19628 x 1.66 x 10⁻²⁷ Kg

                     = 1.9858 x 10⁻²⁷ Kg

speed of light = 3 x 10⁸ m/s

binding energy,

E = mass defect x c²

E = 1.9858 x 10⁻²⁷ x (3 x 10⁸)²

E = 17.87 x 10⁻¹¹ J/atom

now,

binding energy per nucleon =\dfrac{17.87\times 10^{-11}}{136}

                                              = 0.1312 x 10⁻¹¹ J/nucleon

                                              = 1.312 x 10⁻¹² J/nucleon

4 0
3 years ago
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