Calculate the nuclear binding energy per nucleon for 136^Ba if its nuclear mass is 135.905 amu.

Physics

1 answer:

kompoz [17]3 years ago

4 0

Answer:

1.312 x 10⁻¹² J/nucleon

Explanation:

mass of ¹³⁶Ba = 135.905 amu

¹³⁶Ba contain 56 proton and 80 neutron

mass of proton = 1.00728 amu

mass of neutron = 1.00867 amu

mass of ¹³⁶Ba = 56 x 1.00728 amu + 80 x 1.00867 amu

= 137.10128 amu

mass defect = 137.10128 - 135.905

= 1.19628 amu

mass defect = 1.19628 x 1.66 x 10⁻²⁷ Kg

= 1.9858 x 10⁻²⁷ Kg

speed of light = 3 x 10⁸ m/s

binding energy,

E = mass defect x c²

E = 1.9858 x 10⁻²⁷ x (3 x 10⁸)²

E = 17.87 x 10⁻¹¹ J/atom

now,

binding energy per nucleon = $\dfrac{17.87\times 10^{-11}}{136}$

= 0.1312 x 10⁻¹¹ J/nucleon

= 1.312 x 10⁻¹² J/nucleon

You might be interested in

Two forces, one four times as large as the other, pull in the same direction on a 10kg mass and impart to it an acceleration of

notsponge [240]

Answer:

The acceleration of the mass is 2 meters per square second.

Explanation:

By Newton's second law, we know that force ( $F$ ), measured in newtons, is the product of mass ( $m$ ), measured in kilograms, and net acceleration ( $a$ ), measured in meters per square second. That is:

$F = m\cdot a$ (1)

The initial force applied in the mass is:

$F = (10\,kg)\cdot \left(2.5\,\frac{m}{s^{2}} \right)$

$F = 25\,N$

In addition, we know that force is directly proportional to acceleration. If the smaller force is removed, then the initial force is reduced to $\frac{4}{5}$ of the initial force. The acceleration of the mass is: