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arsen [322]
2 years ago
9

the length of two triangles are 5cm and 8cm.the perimeter of the triangle is 20cm.calculate the area of the triangle?​

Mathematics
1 answer:
mote1985 [20]2 years ago
6 0

Step-by-step explanation:

20+8+5=33

33×3=99

hope it helps broo

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Is apples cost $3.50 per pound how much would one and 1/2 pounds cost
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The area of the triangle below is ? Sq. Units <br> A. 66<br> B . 33<br> C . 50 <br> D . 25
kykrilka [37]

Answer:

The answer is B.

Step-by-step explanation:

You have to apply the area of triangle formula :

area =  \frac{1}{2}  \times base \times height

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A baseball player makes it to home plate 35% of the time. How many times can he expect to make it home in 850 at bats
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3 years ago
Evaluate the function at the indicated values if possible. If an indicated value is not in the​ domain, say so.
goldfiish [28.3K]

Answer:

f(-7)=0.

f(2)=-9/5.

f(3) doesn't exist because 3 isn't in the domain of the function.

Step-by-step explanation:

f(x)=\frac{x+7}{x^2-9} is the given function.

We are asked to find:

f(-7)

f(2)

f(3).

f(-7) means to replace x in the expression called f with -7:

Evaluate \frac{x+7}{x^2-9} at x=-7

\frac{(-7)+7}{(-7)^2-9}

\frac{0}{49-9}

\frac{0}{40}

0

So f(-7)=0.

f(2) means to replace x in the expression called f with 2:

Evaluate \frac{x+7}{x^2-9} at x=2

\frac{2+7}{2^2-9}

\frac{9}{4-9}

\frac{9}{-5}

\frac{-9}{5}

So f(2)=-9/5

f(3) means to replace x in the expression called f with 3:

Evaluate \frac{x+7}{x^2-9} at x=3

\frac{3+7}{3^2-9}

\frac{10}{9-9}

\frac{10}{0}

Division by 0 is not allowed so 3 is not in the domain of our function.

5 0
3 years ago
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