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2 years ago

9

the length of two triangles are 5cm and 8cm.the perimeter of the triangle is 20cm.calculate the area of the triangle?

1 answer:

mote1985 [20]2 years ago

6 0

Step-by-step explanation:

20+8+5=33

33×3=99

hope it helps broo

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By calculating the profit that will keep the business going

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3 years ago

Is apples cost $3.50 per pound how much would one and 1/2 pounds cost

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$ 3.50 per lb * 1 1/2 lbs

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3 years ago

The area of the triangle below is ? Sq. Units <br> A. 66<br> B . 33<br> C . 50 <br> D . 25

kykrilka [37]

Answer:

The answer is B.

Step-by-step explanation:

You have to apply the area of triangle formula :

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3 years ago

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A baseball player makes it to home plate 35% of the time. How many times can he expect to make it home in 850 at bats

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3 years ago

Evaluate the function at the indicated values if possible. If an indicated value is not in the domain, say so.

goldfiish [28.3K]

Answer:

f(-7)=0.

f(2)=-9/5.

f(3) doesn't exist because 3 isn't in the domain of the function.

Step-by-step explanation:

$f(x)=\frac{x+7}{x^2-9}$ is the given function.

We are asked to find:

$f(-7)$

$f(2)$

$f(3)$ .

f(-7) means to replace x in the expression called f with -7:

Evaluate $\frac{x+7}{x^2-9}$ at $x=-7$

$\frac{(-7)+7}{(-7)^2-9}$

$\frac{0}{49-9}$

$\frac{0}{40}$

$0$

So f(-7)=0.

f(2) means to replace x in the expression called f with 2:

Evaluate $\frac{x+7}{x^2-9}$ at $x=2$

$\frac{2+7}{2^2-9}$

$\frac{9}{4-9}$

$\frac{9}{-5}$

$\frac{-9}{5}$

So f(2)=-9/5

f(3) means to replace x in the expression called f with 3:

Evaluate $\frac{x+7}{x^2-9}$ at $x=3$

$\frac{3+7}{3^2-9}$

$\frac{10}{9-9}$

$\frac{10}{0}$

Division by 0 is not allowed so 3 is not in the domain of our function.

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3 years ago