2 years ago

The length of a rectangular mailing

Mathematics

1 answer:

anygoal [31]2 years ago

7 0

ANSWER

Let the width be y

2(L + W) = Perimeter

2(2y - 5cm + y) = 62cm

(2×2y) + (2×-5cm) + (2×y) = 62cm

4y + - 10cm + 2y = 62cm

4y - 10cm + 2y = 62cm

4y + 2y - 10cm = 62cm

6y - 10cm + 10cm = 62cm + 10cm

6y = 72cm

6 6

y = 12cm

WIDTH

= y

= 12cm

LENGTH

= 2y - 5cm

= 2×y - 5cm

= 2×12cm - 5cm

= 24cm - 5cm

= 19cm

Providence

19cm + 19cm + 12cm + 12cm = 62cm which is the perimeter

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