The length of a rectangular mailing
1 answer:
<em><u>ANSWER</u></em>
Let the width be y
2(L + W) = Perimeter
2(2y - 5cm + y) = 62cm
(2×2y) + (2×-5cm) + (2×y) = 62cm
4y + - 10cm + 2y = 62cm
4y - 10cm + 2y = 62cm
4y + 2y - 10cm = 62cm
6y - 10cm + 10cm = 62cm + 10cm
<u>6</u><u>y</u> = <u>7</u><u>2</u><u>c</u><u>m</u>
6 6
y = 12cm
<em><u>WIDTH</u></em>
= y
= 12cm
<em><u>LENGTH</u></em>
= 2y - 5cm
= 2×y - 5cm
= 2×12cm - 5cm
= 24cm - 5cm
= 19cm
<em><u>Providence</u></em>
19cm + 19cm + 12cm + 12cm = 62cm which is the perimeter
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