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Rasek [7]
3 years ago
11

The length of a rectangular mailing

Mathematics
1 answer:
anygoal [31]3 years ago
7 0

<em><u>ANSWER</u></em>

Let the width be y

2(L + W) = Perimeter

2(2y - 5cm + y) = 62cm

(2×2y) + (2×-5cm) + (2×y) = 62cm

4y + - 10cm + 2y = 62cm

4y - 10cm + 2y = 62cm

4y + 2y - 10cm = 62cm

6y - 10cm + 10cm = 62cm + 10cm

<u>6</u><u>y</u> = <u>7</u><u>2</u><u>c</u><u>m</u>

6 6

y = 12cm

<em><u>WIDTH</u></em>

= y

= 12cm

<em><u>LENGTH</u></em>

= 2y - 5cm

= 2×y - 5cm

= 2×12cm - 5cm

= 24cm - 5cm

= 19cm

<em><u>Providence</u></em>

19cm + 19cm + 12cm + 12cm = 62cm which is the perimeter

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