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3 years ago

1)If I'm on an elevator that breaks loose and plummets down the shaft, can I avoid harm by jumping at the last second?

Physics

1 answer:

umka2103 [35]3 years ago

5 0

Answer and Explanation:

1) If you were to jump at the last second, you would decrease the impact velocity by 7 mph. This is because most humans have a maximum jump velocity of 7 mph. You may still get hurt, but the damage would be significantly less than if you were to not jump.

2) Bathroom mats are made of fabrics, and fabrics absorb the moisture in the air. If you were to take a shower at any temperature, the fabric will soak up the moisture in the air, so when you touch it, it doesn't feel cold.

The tile floor, however, isn't able to store the moisture into itself. The temperature of the tile will be less than the temperature of your feet.

#teamtrees #PAW (Plant And Water)

I hope this helps!

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A 30 kg male emperor penguin under a clear sky in the Antarctic winter loses very little heat to the environment by convection;

yarga [219]

Answer:

Rate of energy loss by radiation is 28.31 Watt

Explanation:

Given that;

m = 30 kg

power p = 12 W

emissivity e = 0.97

Surface Area A = 0.56 m²

outside of the penguin's body T = −22°C

surroundings Temperature Ts = -38°C

the rate of energy loss by radiation = ?

Now, using Stefan-Boltzmann law;

P = σeA [ T⁴ - Ts⁴ ]

Stefan's constant σ = 5.67 × 10⁻⁸

so we substitute

P = 5.67 × 10⁻⁸ × 0.97 × 0.56 [ (-22 + 273 k)⁴ - (-38 + 273 k )⁴]

= 3.079944 × 10⁻⁸ [ 919325376]

= 28.31 Watt

the rate of energy loss by radiation is 28.31 Watt

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3 years ago

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Anton [14]

Answer:

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Explanation:

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2 years ago

Definition of rolling friction

Deffense [45]

Rolling resistance, sometimes called rolling friction or rolling drag, is the force resisting the motion when a body (such as a ball, tire, or wheel) rolls on a surface.

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3 years ago

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3 years ago

Consider the model above. It represents the electrical force. As r increases, the attractive force decreases. How would this mod

aivan3 [116]

Answer:

As we keep on increasing the radius the value of the gravitation force of attraction decreases and as we decrease the radius the gravitation force increases.

Explanation:

Like the coulombs law of electrostatics, the law of gravitation also depends inversely on the square of the value of r. Therefore, as we keep on increasing the value of r the value of the gravitation force decreases and as we decrease the value of the r the value of gravitation force increases.

Gravitation Force= $\frac{Gm_{1}m_{2} }{r^{2}}$

Coulombs's Law= $\frac{Kq_{1}q_{2} }{r^{2}}$

6 0

4 years ago

Read 2 more answers