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Hunter-Best [27]
3 years ago
5

Give an example of an atom that will give up its outermost electron easily. Explain why you chose this atom.

Physics
1 answer:
BARSIC [14]3 years ago
4 0

Answer:

Cesium (Cs)

very low electronegativity

there are a bunch of cool videos online about Cesium reacting with water

most are faked but the general idea is a cool one as Cesium very quickly and easily gives up it's one and only outermost (or valence) electron

Explanation:

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What is the difference between beta plus and minus
Minchanka [31]
Beta decay is very complex phenomena in natural radioactive decay. There are 3 types of Beta decay.

B+ decay (Beta plus or Beta positive or positron decay):

is the conversion of a proton into a neutron plus a positron and an electron neutrino.

B- decay (Beta negative or Beta nought):

is the conversion  of a neutron into a proton plus an electron and a electron antineutrino. 

Note: a positron is the a positive electron or the antiparticle of the electron.

Hope it helps
7 0
3 years ago
The density of water is 1g/cm3. What is this in kg/m3? The density of water is 1g/cm3. What is this in kg/m3? Follow 3 answers 3
Lelu [443]
1 gram per cubic centimeter is equal to 1000 kilograms per cubic meter. Just multiply it with a 1000 and you have your solution.
8 0
4 years ago
What is the mass of one mole of carbon dioxide in sl?​
ra1l [238]

Answer:

Around 44.01g.

Explanation:

One mole of carbon dioxide molecules has a mass of 44.01g, while one mole of sodium sulfide formula units has a mass of 78.04g.

8 0
3 years ago
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PolarNik [594]

Answer:

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Explanation:

5 0
3 years ago
Read 2 more answers
Case 1: A DJ starts up her phonograph player. The turntable accelerates uniformly from rest, and takes t₁ = 11.9 seconds to get
olga_2 [115]

Answer:

Part a)

\omega = 8.17 rad/s

Part b)

N = 7.74 rev

Part c)

\alpha = 0.69 rad/s^2

Part d)

\alpha = 0.48 rad/s^2

Part e)

t = 9.14 s

Explanation:

Part a)

Angular speed is given as

\omega = 2\pi f

\omega = 2\pi(\frac{78}{60})

\omega = 8.17 rad/s

Part b)

Since turn table is accelerating uniformly

so we will have

\theta = \frac{\omega_f + \omega_i}{2} t

\theta = \frac{8.17 + 0}{2}(11.9)

2N\pi = 48.6

N = 7.74 rev

Part c)

angular acceleration is given as

\alpha = \frac{\omega_f - \omega_i}{t}

\alpha = \frac{8.17 - 0}{11.9}

\alpha = 0.69 rad/s^2

Part d)

When its angular speed changes to 120 rpm

then we will have

\omega_2 = 2\pi (\frac{120}{60})

\omega_2 = 12.56 rad/s

number of turns revolved is 15 times

so we have

\omega_f^2 - \omega_i^2 = 2 \alpha \theta

12.56^2 - 8.17^2 = 2\alpha (2\pi\times 15)

\alpha = 0.48 rad/s^2

Part e)

now for uniform acceleration we have

\omega_f - \omega_i = \alpha t

12.56 - 8.17 = 0.48 t

t = 9.14 s

7 0
3 years ago
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