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Hoochie [10]
2 years ago
9

How do you factorise 3x²-x​

Mathematics
1 answer:
never [62]2 years ago
4 0

Answer:

x(3x-1)

Step-by-step explanation:

take the similar ones out

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Round your answer to the nearest tenth.
Kruka [31]

Answer:

The value of MB = 8.4

Step-by-step explanation:

We know that the point of intersection of the Medians of a triangle is called the centroid of a triangle.

Thus,

For the given triangle ΔJKL,

  • The point M is the centroid of the triangle.

We also know that the centroid is 2/3 of the distance from each vertex to the midpoint of the opposite side.

Also, each Median is split into two parts such that the longer part is 2 times the length of the smaller part.

In our case,

The median KB is split into two parts such that the longer part KM is 2 times the length of the smaller part MB.

i.e.

KM = 2 MB

Given KM = 16.8

so substitute KM = 16.8 in the equation KM = 2 MB

16.8 = 2 MB

MB = 16.8/2

MB = 8.4

Therefore, the value of MB = 8.4

7 0
3 years ago
Read 2 more answers
Use the four-step definition of the derivative to find f'(x) if f(x) = −4x^3 −1.
guapka [62]

\stackrel{de finition \textit{ of a derivative as a limit}}{\lim\limits_{h\to 0}~\cfrac{f(x+h)-f(x)}{h}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{[-4(x+h)^3-1]~~ - ~~[-4x^3-1]}{h} \\\\\\ \cfrac{[-4(x^3+3x^2h+3xh^2+h^3)-1]~~ ~~+4x^3+1}{h} \\\\\\ \cfrac{[-4x^3-12x^2h-12xh^2-4h^3-1]~~ ~~+4x^3+1}{h} \\\\\\ \cfrac{-4x^3-12x^2h-12xh^2-4h^3-1+4x^3+1}{h}\implies \cfrac{-12x^2h-12xh^2-4h^3}{h}

\cfrac{h(-12x^2-12xh-4h^2)}{h}\implies -12x^2-12xh-4h^2 \\\\\\ \lim\limits_{h\to 0}~-12x^2-12xh-4h^2\implies \lim\limits_{h\to 0}~-12x^2-12x(0)-4(0)^2 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \lim\limits_{h\to 0}~-12x^2~\hfill

7 0
2 years ago
Solve the Quadratic equation
GrogVix [38]

Answer:

kindly using which rule?

7 0
2 years ago
Hellpppppppopppppppppppppp meeeeeeeeee pleassssse
Ilya [14]
????I don’t get what u need help with
5 0
2 years ago
Will mark brainliest if answered fast enough
vekshin1

Answer:

Option D that is y=-2(x+1) is the correct choice.

Explanation:

Given equation:

y=2x-2

We have to find another equation which has only one solution.

Standard form of equation:

1.a_1x+b_1y+c_1=0

2.a_2x+b_2y+c_2=0

Condition for one solution.

\frac{a_1}{a_2} \neq \frac{b_1}{b_2}

We have to arrange other equation in the form of  ax+by+c=0

Mark all the options as a,b,c and d.

a.\ 2x+1-y=0

b.\ 2x-2-y=0

c.\ 2x-4-y=0

d.-2x-2-y=0

Now from the above options we can see that option a,b\ and\ c are not providing the desired result.

So

\frac{a_1}{a_2} \neq \frac{b_1}{b_2} can be obtained from the last option.

As

\frac{a_1}{a_2} \neq \frac{b_1}{b_2} ,\frac{2}{-2} \neq \frac{-1}{-1} ,-1\neq 1

Option D that is y=-2(x+1) is the equation from where we can obtained only one solution.

4 0
3 years ago
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