3 years ago

How do you prove that the action and reaction forces act on 2 different object according to Newtons III Law of motion.?

1 answer:

8 0

If both the forces acted on the same object they would cancel each other and the resultant would be 0 and we will not be able to do things like pushing a box.

You might be interested in

WILL MARK BRAINLIEST<br> If it takes you 70s to run the track, what is your velocity?

tiny-mole [99]

Answer:

Explanation:

But you have to be fat though lol

5 0

2 years ago

What factors cause a rock to become metamorphic

Lynna [10]

Pressure and heat. I hope this helps

3 0

2 years ago

Read 2 more answers

Because the earth's orbit is slightly elliptical, the earth actually gets closer to the sun during part of the year. When the ea

BabaBlast [244]

Closer to the sun . . . orbital speed is faster.

Farther from the sun . . . orbital speed is slower.

Flag answer: Answer 13 Answer 13

5 0

2 years ago

Pretty cool, the atoms that exist in your body are some of the same atoms that have existed since the beginning of the universe.

marusya05 [52]

Answer:

was is carl sagan?

Explanation:

please forgive me if im wrong :(

8 0

2 years ago

Read 2 more answers

Part complete How long must a simple pendulum be if it is to make exactly one swing per five seconds?

shtirl [24]

Answer:

$L=6.21m$

Explanation:

For the simple pendulum problem we need to remember that:

$\frac{d^{2}\theta}{dt^{2}}+\frac{g}{L}sin(\theta)=0$ ,

where $\theta$ is the angular position, t is time, g is the gravity, and L is the length of the pendulum. We also need to remember that there is a relationship between the angular frequency and the length of the pendulum:

$\omega^{2}=\frac{g}{L}$ ,

where $\omega$ is the angular frequency.

There is also an equation that relates the oscillation period and the angular frequeny:

$\omega=\frac{2\pi}{T}$ ,

where T is the oscillation period. Now, we can easily solve for L:

$(\frac{2\pi}{T})^{2}=\frac{g}{L}\\\\L=g(\frac{T}{2\pi})^{2}\\\\L=9.8(\frac{5}{2\pi})^{2}\\\\L=6.21m$

3 0

3 years ago