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natali 33 [55]
3 years ago
15

A package was determined to have a mass of 5.7 kilograms. What's the force of gravity acting on the package on earth?

Physics
2 answers:
Arturiano [62]3 years ago
8 0
1.) The force of gravity is what we call weight, we define it as:
w=mg
w=5,7kg*9,8m/s²
w=55,86kg (b)
2.) We know that:
power=W/t
power=50J/20s
power=2,5Watts (a)
3.) The work done is equal to the potential energy, so:
Epg=mgh
Epg=63kg*9,8m/s²*7m
Epg=4321J
Now we get the power:
power=W/t
power=4321J/5s
power=864Watts
Now:
1HP=746Watts
=1,16HP (b)
4.) We know that:
F=ma
350N=m*10m/s²
m=350N/10m/s²
m=35kg (b)
5.) d.) Aceleration is tha rate of change in velocity, either positive (increasing) or negative (decreasing)
Simora [160]3 years ago
7 0
==>  A package was determined . . .

                   Weight = (mass) x (gravity)

Gravity on Earth = 9.8 m/s²

                   Weight = (5.7 kg) x (9.8 m/s²)

                               =  55.86 kg-m/s² .                 1 kg-m/s² = 1 N

==> 50 J of work was performed . . .

     Power = (work done) / (time to do the work)

                 =  (50 J)  /  (20 sec)

                 =    2.5 J/sec                    1 J/sec = 1 watt

==> A 63-kg object needs . . .

       Weight = (mass) x (gravity)
       Work = (force) x (distance)
       Power = (work done) / (time to do the work)

So  Power = (mass) x (gravity) x (distance) / (time to lift)

                   = (63 kg) x (9.8 m/s²) x (7 m)  /  (5 sec)

                   =  (63 x 9.8 x 7) / (5)     (kg-m²/s²) / (sec)

                   =          864.36 joules/sec

Convert                  (864.36 watts) x (1 HP/746 watts)  =  1.159 HP

(How to remember the conversion from watts to Horsepower:
    The sails on Columbus' ship the Santa Maria developed 2 HP at top wind.
     1492 / 2  =  746 watts per HP.  )

==> A force of 350 N  causes . . .

         Force  = (mass) x (acceleration)

         Mass  =  (force) / (acceleration)

                   =  (350 kg-m/s²) / (10 m/s²)

                   =        35 kg.

==> Which of the following . . .

         Golden Rule:  "Acceleration means any change in velocity,
                                   including change in speed or direction."

A).  No.  Constant velocity means zero acceleration.
B).  No.  When people say "decelerating" they mean "slowing down".
               That's decreasing magnitude of velocity.
C). Yes.  'Acceleration' does NOT mean 'speeding up'.   Any change
               in speed or direction, even slowing down, is acceleration.
D). Yes.  If an object's velocity is changing, then either the speed or direction of its motion is changing, and either of those is 'acceleration'.  The object doesn't need to be speeding up or slowing down, but if its direction is changing, then that's called 'acceleration.  Rounding a curve at a constant speed, or driving a circle with constant speed, are both examples of 'acceleration'.
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A spring that is compressed 14.5 cm from its equilibrium position stores 2.99 J of potential energy. Determine the spring consta
strojnjashka [21]

Answer:

284.4233 N/m

Explanation:

k = Spring constant

x = Compression of spring = 14.5 cm

U = Potential energy = 2.99 J

The potential energy of a spring is given by

U=\dfrac{1}{2}kx^2

Rearranging to get the value of k

\\\Rightarrow k=\dfrac{2U}{x^2}\\\Rightarrow k=\dfrac{2\times 2.99}{0.145^2}\\\Rightarrow k=284.4233\ N/m

The spring constant is 284.4233 N/m

7 0
3 years ago
An Austin volleyball player bumps a 5 kg ball into the air. It reaches a height of 2.8 meters. How fast was the ball going as it
KATRIN_1 [288]

Answer:

v = 7.4 m/s

Explanation:

Given that,

Mass if a volleyball, m = 5 kg

The ball reaches a height of 2.8 m

We need to find how fast the ball is going as it bumped into the air. Ket the velocity is v. Using the conservation of energy to find it as follows :

mgh=\dfrac{1}{2}mv^2\\\\v=\sqrt{2gh} \\\\v=\sqrt{2\times 9.8\times 2.8} \\\\=7.4\ m/s

So, the required speed is 7.4 m/s. Hence, the correct option is (b).

6 0
3 years ago
Thomas and John are carrying a 43kg cylinder head on a 510cm X 510mm board. The cylinder head with dimensions of 43cm X 250mm li
tatyana61 [14]

John carry the heaviest load.

<h3>How to find out who is carrying the heavy load?</h3>

Write down given data from questions:

Board=510cm X 510mm.

Cylinder head with dimensions=43cm X 250mm.

Cylinder lies across the board 210cm from john.

Find out: Who is carry the heaviest load?​

Calculation:

We assume that mass of cylinder head = x kg

Then weight=x x 9*81

                 W=9.81x  Newton.

Weight per unit length= Weight/Total leanth

Weight per unit length= 9.81x/43

(w/l)=0.23x N/cm

From equation contition: (F_{J} +F_{T} =9.81x n)

F_{T} (510)=9.81x  (210+21.5)

F_{T} (510)=9.81 x (231.5)

F_{T} =4.452x N.

F_{J} =9.81x-4.452x

F_{J} =5.358 xN

Therefore F_{J} \geq F_{T}

To learn more about mass per unit length, refer to:

brainly.com/question/24180692

#SPJ9

4 0
2 years ago
If you have two wires made out of the same material and the same thickness, one is 3-inches long and one is 6-inches long, which
andreyandreev [35.5K]

Answer:

3 inch long wire

Explanation:

it is shorter

4 0
3 years ago
Read 2 more answers
A spring is pulled to 10cm and held in place with a force of 500N. What is the spring constant of the spring
MrMuchimi

Answer:

5000

Explanation:

F=ke where f is the force, k is the spring constant, e is the extension....all in standard units

4 0
3 years ago
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