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natali 33 [55]
3 years ago
15

A package was determined to have a mass of 5.7 kilograms. What's the force of gravity acting on the package on earth?

Physics
2 answers:
Arturiano [62]3 years ago
8 0
1.) The force of gravity is what we call weight, we define it as:
w=mg
w=5,7kg*9,8m/s²
w=55,86kg (b)
2.) We know that:
power=W/t
power=50J/20s
power=2,5Watts (a)
3.) The work done is equal to the potential energy, so:
Epg=mgh
Epg=63kg*9,8m/s²*7m
Epg=4321J
Now we get the power:
power=W/t
power=4321J/5s
power=864Watts
Now:
1HP=746Watts
=1,16HP (b)
4.) We know that:
F=ma
350N=m*10m/s²
m=350N/10m/s²
m=35kg (b)
5.) d.) Aceleration is tha rate of change in velocity, either positive (increasing) or negative (decreasing)
Simora [160]3 years ago
7 0
==>  A package was determined . . .

                   Weight = (mass) x (gravity)

Gravity on Earth = 9.8 m/s²

                   Weight = (5.7 kg) x (9.8 m/s²)

                               =  55.86 kg-m/s² .                 1 kg-m/s² = 1 N

==> 50 J of work was performed . . .

     Power = (work done) / (time to do the work)

                 =  (50 J)  /  (20 sec)

                 =    2.5 J/sec                    1 J/sec = 1 watt

==> A 63-kg object needs . . .

       Weight = (mass) x (gravity)
       Work = (force) x (distance)
       Power = (work done) / (time to do the work)

So  Power = (mass) x (gravity) x (distance) / (time to lift)

                   = (63 kg) x (9.8 m/s²) x (7 m)  /  (5 sec)

                   =  (63 x 9.8 x 7) / (5)     (kg-m²/s²) / (sec)

                   =          864.36 joules/sec

Convert                  (864.36 watts) x (1 HP/746 watts)  =  1.159 HP

(How to remember the conversion from watts to Horsepower:
    The sails on Columbus' ship the Santa Maria developed 2 HP at top wind.
     1492 / 2  =  746 watts per HP.  )

==> A force of 350 N  causes . . .

         Force  = (mass) x (acceleration)

         Mass  =  (force) / (acceleration)

                   =  (350 kg-m/s²) / (10 m/s²)

                   =        35 kg.

==> Which of the following . . .

         Golden Rule:  "Acceleration means any change in velocity,
                                   including change in speed or direction."

A).  No.  Constant velocity means zero acceleration.
B).  No.  When people say "decelerating" they mean "slowing down".
               That's decreasing magnitude of velocity.
C). Yes.  'Acceleration' does NOT mean 'speeding up'.   Any change
               in speed or direction, even slowing down, is acceleration.
D). Yes.  If an object's velocity is changing, then either the speed or direction of its motion is changing, and either of those is 'acceleration'.  The object doesn't need to be speeding up or slowing down, but if its direction is changing, then that's called 'acceleration.  Rounding a curve at a constant speed, or driving a circle with constant speed, are both examples of 'acceleration'.
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The black lines that wrap themselves around a basketball represent an example of what type of geometry?
Dmitry [639]
In Euclidean geometry parallel lines never intersect. But in non-Euclidean geometry parallel lines can either curve away from each other, or curve towards each other. Example : the black lines that wrap themselves around the basketball.
Answer: B ) non-Euclidean 
5 0
3 years ago
A fullback preparing to carry the football starts from rest and accelerates straight ahead. He is handed the ball just before he
RideAnS [48]

Answer:

x=4.06m

Explanation:

A body that moves with constant acceleration means that it moves in "a uniformly accelerated movement", which means that if the velocity is plotted with respect to time we will find a line and its slope will be the value of the acceleration, it determines how much it changes the speed with respect to time.

When performing a mathematical demonstration, it is found that the equations that define this movement are as follows.

Vf=Vo+a.t  (1)\\\\

{Vf^{2}-Vo^2}/{2.a} =X(2)\\\\

X=Xo+ VoT+0.5at^{2}    (3)\\

Where

Vf = final speed

Vo = Initial speed

T = time

A = acceleration

X = displacement

In conclusion to solve any problem related to a body that moves with constant acceleration we use the 3 above equations and use algebra to solve

for this problem

Vf=7.6m/s

t=1.07

Vo=0

we can use the ecuation number one to find the acceleration

a=(Vf-Vo)/t

a=(7.6-0)/1.07=7.1m/s^2

then we can use the ecuation number 2 to find the distance

{Vf^{2}-Vo^2}/{2.a} =X

(7.6^2-0^2)/(2x7.1)=4.06m

4 0
3 years ago
An archer draws her bow and stores 34.8 J of elastic potential energy in the bow. She releases the 63 g arrow, giving it an init
elena-14-01-66 [18.8K]

Answer:

Approximately 71\%.

Explanation:

The formula for the kinetic energy \rm KE of an object is:

\displaystyle \mathrm{KE} = \frac{1}{2}\, m \cdot v^2,

where

  • m is the mass of that object, and
  • v is the speed of that object.

Important: Joule (\rm J) is the standard unit for energy. The formula for \rm KE requires two inputs: mass and speed. The standard unit of mass is \rm kg while the standard unit for speed is \rm m \cdot s^{-1}. If both inputs are in standard units, then the output (kinetic energy) will also be in the standard unit (that is: joules,

Convert the unit of the arrow's mass to standard unit:

m = 63\; \rm g = 0.063\; \rm kg.

Initial \rm KE of this arrow:

\begin{aligned}\mathrm{KE} &= \frac{1}{2} \, m \cdot v^2 \\ &= \frac{1}{2}\times 0.063\; \rm kg \times \left(\rm 28 \; m \cdot s^{-1}\right)^2 \\ &\approx 24.696\; \rm J\end{aligned}.

That's the same as the energy output of this bow. Hence, the efficiency of energy transfer will be:

\displaystyle \frac{24.696\; \rm J}{34.8\; \rm J} \times 100\% \approx 71\%.

8 0
3 years ago
an object has a length of 5.0 cm, aheight of 3.0 cm and a width of 15.0 cm. it has a mass of 24 grams. what is its density?
kondaur [170]
5x3=N
Nx15=F
Fx24=Your Awnser
5 0
3 years ago
Answer all please!!!!!!!!!!✌​
Nina [5.8K]

Answer:

koj ruam zog

Explanation:

7 0
3 years ago
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