Because sound waves don't travel through the vaccume of space. Hope this helped
Answer:
v = 3.27 m/s
Explanation:
KE = 1/2 mv^2
695 J = 1/2 (130kg)(v^2)
695 J / (1/2 x 130kg) = v^2
v^2 = square root of 10.69
v = 3.27 m/s
I would think 2.759kmockinbirds if you consider mockingbirds equal to a metre and kmockinbird to kilometres
Answer:
The value of the power is 
Explanation:
From the question we are told that
The power rating 
The frequency is 
The frequency at which the sound intensity decreases 
The decrease in intensity is by 
Generally the initial intensity of the speaker is mathematically represented as
![\beta_1 = 10 log_{10} [\frac{P_b}{P_a} ]](https://tex.z-dn.net/?f=%5Cbeta_1%20%3D%20%2010%20log_%7B10%7D%20%5B%5Cfrac%7BP_b%7D%7BP_a%7D%20%5D)
Generally the intensity of the speaker after it has been decreased is
![\beta_2 = 10 log_{10} [\frac{P_c}{P_a} ]](https://tex.z-dn.net/?f=%5Cbeta_2%20%3D%20%2010%20log_%7B10%7D%20%5B%5Cfrac%7BP_c%7D%7BP_a%7D%20%5D)
So
![\beta_1-\beta_2 = 10 log_{10} [\frac{P_c}{P_a} ]- 10 log_{10} [\frac{P_b}{P_a} ]](https://tex.z-dn.net/?f=%5Cbeta_1-%5Cbeta_2%20%3D%20%2010%20log_%7B10%7D%20%5B%5Cfrac%7BP_c%7D%7BP_a%7D%20%5D-%2010%20log_%7B10%7D%20%5B%5Cfrac%7BP_b%7D%7BP_a%7D%20%5D)
=> ![\beta = 10 log_{10} [\frac{P_c}{P_a} ]- 10 log_{10} [\frac{P_b}{P_a} ]= 1.3](https://tex.z-dn.net/?f=%5Cbeta%20%3D%20%2010%20log_%7B10%7D%20%5B%5Cfrac%7BP_c%7D%7BP_a%7D%20%5D-%2010%20log_%7B10%7D%20%5B%5Cfrac%7BP_b%7D%7BP_a%7D%20%5D%3D%201.3)
=> ![\beta =10log_{10} [\frac{\frac{P_b}{P_a}}{\frac{P_c}{P_a}} ] = 1.3](https://tex.z-dn.net/?f=%5Cbeta%20%3D10log_%7B10%7D%20%5B%5Cfrac%7B%5Cfrac%7BP_b%7D%7BP_a%7D%7D%7B%5Cfrac%7BP_c%7D%7BP_a%7D%7D%20%5D%20%3D%201.3)
=> ![\beta =10log_{10} [\frac{P_b}{P_c} ] = 1.3](https://tex.z-dn.net/?f=%5Cbeta%20%3D10log_%7B10%7D%20%5B%5Cfrac%7BP_b%7D%7BP_c%7D%20%5D%20%3D%201.3)
=> ![10log_{10} [\frac{P_b}{P_c} ] = 1.3](https://tex.z-dn.net/?f=10log_%7B10%7D%20%5B%5Cfrac%7BP_b%7D%7BP_c%7D%20%5D%20%3D%201.3)
=> ![log_{10} [\frac{P_b}{P_c} ] = 0.13](https://tex.z-dn.net/?f=log_%7B10%7D%20%5B%5Cfrac%7BP_b%7D%7BP_c%7D%20%5D%20%3D%200.13)
taking atilog of both sides
=>
=> 
=> 
Answer:
D = 4 m
Explanation:
Speed of cart in air track v₁ = 0.5 m/s
Speed of cart moved when air is turned off v₂= 1 m/s
The distance travelled by the cart is d₁ = 1 m
Work done (W) = F x d
Work done is equal to the kinetic energy
F x d = 1/2mv²
velocity is directly proportional to distance
therefore,
v₁²/ v₂² = d₁ / d₂
d₂ = d₁v₂² / v₁²
= 1 m x (1 m /s)² / (0.5 m/s)²
= 4 m