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Rainbow [258]
3 years ago
9

What are the benefits to resistance training ?

Physics
1 answer:
shutvik [7]3 years ago
8 0
Improved muscle strength and tone – to protect your joints from injury.
maintaining flexibility and balance, which can help you remain independent as you age.
weight management and increased muscle-to-fat ratio – as you gain muscle, your body burns more kilojoules when at rest.
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How do lone pairs of electrons affect the bond angle differently than electrons shared in a bond?
lubasha [3.4K]

Answer:

Lone pairs cause bond angles to deviate away from the ideal bond angles

Explanation:

Bonded electrons are stabilized and clustered between the bonding electrons meaning they are much closer together. Non-bonding electrons however are not being shared between any atoms which allows them to roam a little further spreading the charge density over a larger space and therefore interfering with what would be an expected bond angle

3 0
3 years ago
A 6kg rock rolls down a hill with a momentum of 12kg m/s . Work out the velocity of the rock
Nat2105 [25]

Answer:

if you need to get the work=force×displacement or if you need the velocity=displacement÷time taken

7 0
2 years ago
Read 2 more answers
an electric current 0.75 a passes through a circuit that has a resistance of 175. according to ohm's law, what is the voltage of
Aleksandr [31]

Answer:

131.25

Explanation:

i worked it out on a diffrent sheet so its hard to explain

8 0
3 years ago
Which of the following is an example of chemical change?
Maru [420]

Answer:

c

Explanation:

all the others r physical

8 0
3 years ago
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A girl rolls a ball up an incline and allows it to re- turn to her. For the angle and ball involved, the acceleration of the bal
zalisa [80]

Answer:

3.28 m

3.28 s

Explanation:

We can adopt a system of reference with an axis along the incline, the origin being at the position of the girl and the positive X axis going up slope.

Then we know that the ball is subject to a constant acceleration of 0.25*g (2.45 m/s^2) pointing down slope. Since the acceleration is constant we can use the equation for constant acceleration:

X(t) = X0 + V0 * t + 1/2 * a * t^2

X0 = 0

V0 = 4 m/s

a = -2.45 m/s^2 (because the acceleration is down slope)

Then:

X(t) = 4*t - 1.22*t^2

And the equation for speed is:

V(t) = V0 + a * t

V(t) = 4 - 2.45 * t

If we equate this to zero we can find the moment where it stops and begins rolling down, that will be the highest point:

0 = 4 - 2.45 * t

4 = 2.45 * t

t = 1.63 s

Replacing that time on the position equation:

X(1.63) = 4 * 1.63 - 1.22 * 1.63^2 = 3.28 m

To find the time it will take to return we equate the position equation to zero:

0 = 4 * t - 1.22 * t^2

Since this is a quadratic equation it will have to answers, one will be the moment the ball was released (t = 0), the other will eb the moment when it returns:

0 = t * (4 - 1.22*t)

t1 = 0

0 = 4 - 1.22*t2

1.22 * t2 = 4

t2 = 3.28 s

7 0
3 years ago
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